从汇编代码中删除控制指令并查找依赖项

Question

根据评论编辑问题:

我有一个汇编代码文件，其指令安排如下:

Line[1]:       | [wrr a10,a9] [add a8,a10,a3] [ld.n a8,a8,16]                                                              
Line[2]:       | [add a8,a10,a3] [ld.n a8,a8,16] [call a8]                                                                 
Line[3]:       | [ld.n a8,a8,16] [call a8] [entry a1,32]                                                                      
Line[4]:       | [call a8] [entry a1,32] [ld a8,0x1fff8910]                                                                   
Line[5]:       | [entry a1,32] [ld a8,0x1fff8910] [ext a3,a2,0,8]                                                             
Line[6]:       | [st.n a15,a1,12] [st.n a12,a1,16] [st.n a9,a1,8]                                                            
Line[7]:       | [ext a3,a2,0,8] [sll a3,a3,4] [add.n a3,a3,a8]                                                                
Line[8]:       | [sll a3,a3,4] [add.n a3,a3,a8] [ld a11,a3,128]    

我想删除下面列表中描述的控制指令和指令中出现的任何两个后续加载存储:

control_instructions = ['call', 'entry', 'j']
2_consecutive_remove = ['st', 'ld]

(如果有ld ld或st st出现在一行的连续两个列表项中，我必须删除该行)

由于call和entry出现在第2-5行，并且第6行连续有两个st指令，因此我的输出应该只打印第1、7、8行

我试着用下面的代码删除控制指令，但它似乎不起作用。如有任何帮助，不胜感激

new_lines = [line for line in old_lines if not any(x in y for x in control_instructions for y in line )]

Answer 1

你有一个文件，而不是一个列表，所以:

control_instructions = ['call', 'entry', 'j']
cleaned = []
consecutive_remove = ['st.n', 'ld']
with open("your_log.txt") as f:
    for line in f:
        if not any(x in line for x in control_instructions) and sum(line.count(x) for x in consecutive_remove)  <= 1 :
            cleaned.append(line)
            print line
Line[1]: | [wrr a10,a9] [add a8,a10,a3] [ld.n a8,a8,16]
Line[7]: | [ext a3,a2,0,8] [sll a3,a3,4] [add.n a3,a3,a8]
Line[8]: | [sll a3,a3,4] [add.n a3,a3,a8] [ld a11,a3,128]