neo4j 弹簧数据 无法识别的字段"meta"

Question

我开始使用Neo4j和spring数据。

我可以访问数据库，但不能制作一套。

当我尝试使用save方法时，会发生此错误。这似乎是因为杰克逊没有意识到的领域。我寻找解决方案，但没有成功。

有人能帮我吗？

   10:52:49.481 [http-nio-8080-exec-2] INFO  o.s.d.n.config.Neo4jConfiguration - Initialising Neo4jSession
10:52:51.617 [http-nio-8080-exec-2] ERROR o.n.o.s.response.RowModelResponse - failed to parse: {"row":[1],"meta":[null]}]}
10:52:51.694 [http-nio-8080-exec-2] INFO  o.s.d.n.config.Neo4jConfiguration - Intercepted exception
May 13, 2016 10:52:56 AM org.apache.catalina.core.StandardWrapperValve invoke
SEVERE: Servlet.service() for servlet [DispatcherServlet] in context with path [/ProjetoExemplo] threw exception [Request processing failed; nested exception is java.lang.RuntimeException: com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException: Unrecognized field "meta" (class org.neo4j.ogm.session.result.RowModelResult), not marked as ignorable (one known property: "row"])
 at [Source: {"row":[1],"meta":[null]}]}; line: 1, column: 20] (through reference chain: org.neo4j.ogm.session.result.RowModelResult["meta"])] with root cause
com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException: Unrecognized field "meta" (class org.neo4j.ogm.session.result.RowModelResult), not marked as ignorable (one known property: "row"])
 at [Source: {"row":[1],"meta":[null]}]}; line: 1, column: 20] (through reference chain: org.neo4j.ogm.session.result.RowModelResult["meta"])
    at com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException.from(UnrecognizedPropertyException.java:51)
    at com.fasterxml.jackson.databind.DeserializationContext.reportUnknownProperty(DeserializationContext.java:731)
    at com.fasterxml.jackson.databind.deser.std.StdDeserializer.handleUnknownProperty(StdDeserializer.java:915)
    at com.fasterxml.jackson.databind.deser.BeanDeserializerBase.handleUnknownProperty(BeanDeserializerBase.java:1292)
    at com.fasterxml.jackson.databind.deser.BeanDeserializerBase.handleUnknownVanilla(BeanDeserializerBase.java:1270)
    at com.fasterxml.jackson.databind.deser.BeanDeserializer.vanillaDeserialize(BeanDeserializer.java:247)
    at com.fasterxml.jackson.databind.deser.BeanDeserializer.deserialize(BeanDeserializer.java:118)
    at com.fasterxml.jackson.databind.ObjectMapper._readMapAndClose(ObjectMapper.java:3051)
    at com.fasterxml.jackson.databind.ObjectMapper.readValue(ObjectMapper.java:2146)
    at org.neo4j.ogm.session.response.RowModelResponse.next(RowModelResponse.java:45)
    at org.neo4j.ogm.session.response.SessionResponseHandler.updateObjects(SessionResponseHandler.java:93)
    at org.neo4j.ogm.session.delegates.SaveDelegate.save(SaveDelegate.java:69)
    at org.neo4j.ogm.session.delegates.SaveDelegate.save(SaveDelegate.java:43)
    at org.neo4j.ogm.session.Neo4jSession.save(Neo4jSession.java:386)

我的班级：

 @NodeEntity
 @JsonIgnoreProperties(ignoreUnknown = true)
 public class Teste {
@JsonProperty("id")
private Long id;
public Long getId() {
    return id;
}
private String name;
public Teste(){
}
public String getName() {
    return name;
}
public void setName(String name) {
    this.name = name;
}
@Override
public int hashCode() {
    final int prime = 31;
    int result = 1;
    result = prime * result + ((id == null) ? 0 : id.hashCode());
    return result;
}
@Override
public boolean equals(Object obj) {
    if (this == obj)
        return true;
    if (obj == null)
        return false;
    if (getClass() != obj.getClass())
        return false;
    Teste other = (Teste) obj;
    if (id == null) {
        if (other.id != null)
            return false;
    } else if (!id.equals(other.id))
        return false;
    return true;
}

我的电话：

    Teste teste1 = new Teste();
    teste1.setName("TESTE");        
    testeService.save(teste1);

Answer 1

看起来您正在使用Neo4j 3？如果是这样，那么您使用的SDN版本可能不兼容。Neo4j 3.0兼容这些：

• SDN 4.2:4.2.0.BUILD-snapshot的当前快照
• SDN 4.1.1：4.1.1.与neo4j ogm 2.0.2一起发布