我正在尝试使用 Base64 对我的 sharedPreferences 用户名和密码进行编码,但是在 eclipse 模拟器中运行我的程序时,我收到错误消息说"数组越界"。我不确定此错误是什么意思以及如何纠正它。
日志猫:
10-06 13:51:24.005: E/AndroidRuntime(4272): FATAL EXCEPTION: main
10-06 13:51:24.005: E/AndroidRuntime(4272): java.lang.ArrayIndexOutOfBoundsException: length=3; index=3
10-06 13:51:24.005: E/AndroidRuntime(4272): at com.SharedPreferences.Login.SharedPrefLoginActivity.onClick(SharedPrefLoginActivity.java:84)
10-06 13:51:24.005: E/AndroidRuntime(4272): at android.view.View.performClick(View.java:3511)
10-06 13:51:24.005: E/AndroidRuntime(4272): at android.view.View$PerformClick.run(View.java:14105)
10-06 13:51:24.005: E/AndroidRuntime(4272): at android.os.Handler.handleCallback(Handler.java:605)
10-06 13:51:24.005: E/AndroidRuntime(4272): at android.os.Handler.dispatchMessage(Handler.java:92)
10-06 13:51:24.005: E/AndroidRuntime(4272): at android.os.Looper.loop(Looper.java:137)
10-06 13:51:24.005: E/AndroidRuntime(4272): at android.app.ActivityThread.main(ActivityThread.java:4424)
10-06 13:51:24.005: E/AndroidRuntime(4272): at java.lang.reflect.Method.invokeNative(Native Method)
10-06 13:51:24.005: E/AndroidRuntime(4272): at java.lang.reflect.Method.invoke(Method.java:511)
10-06 13:51:24.005: E/AndroidRuntime(4272): at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:784)
10-06 13:51:24.005: E/AndroidRuntime(4272): at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:551)
10-06 13:51:24.005: E/AndroidRuntime(4272): at dalvik.system.NativeStart.main(Native Method)
这是我的注册活动,它应该采用 EditText 字符串、编码并保存到共享首选项 xml。
public void onClick(View arg0) {
user=rName.getText().toString().trim();
pass=rPwd.getText().toString().trim();
if(arg0==regBttn){
if((user.length()!=0))
{
if((pass.length()!=0))
{
sp=getSharedPreferences("AccessApp",MODE_WORLD_WRITEABLE);
Editor myEditor=sp.edit();
try {
myEditor.putString("USERNAME_KEY", user);
byte[ ] superSecretKeyBytes = Base64.decode(user);
byte[] key = { 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 0, 1, 2, 3, 4, 5, 6 };
for (int i = 0; i < pass.length(); i++) {
key[i] = superSecretKeyBytes[i];
}
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
try {
myEditor.putString("PASSWORD_KEY", pass);
byte[ ] superSecretKeyBytes = Base64.decode(pass);
byte[] key = { 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 0, 1, 2, 3, 4, 5, 6 };
for (int i = 0; i < pass.length(); i++) {
key[i] = superSecretKeyBytes[i];
}
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
myEditor.commit();
Toast.makeText(this, "Registration is successfull",10000).show();
i=new Intent(this,AccessApp.class);
startActivity(i);
}
else
{
Toast.makeText(this, "Please Enter password", 10000).show();
}
}
else{
Toast.makeText(this,"Please Enter Username",10000).show();
}
}
else if(arg0==rtnBttn){
AlertDialog.Builder builder=new AlertDialog.Builder(this);
builder.setTitle("Exit");
builder.setMessage("Do you want to exit");
builder.setCancelable(false);
builder.setPositiveButton("Yes",new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int which) {
// TODO Auto-generated method stub
finish();
}
});
builder.setNegativeButton("No", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface arg0, int arg1) {
arg0.cancel();
}
});
AlertDialog alert=builder.create();
alert.show();
}
}
public String encrypt(String toencrypt, byte key[]) throws Exception {
SecretKeySpec secret = new SecretKeySpec(key, "AES");
Cipher cipher = Cipher.getInstance("AES");
cipher.init(Cipher.ENCRYPT_MODE, secret);
byte[] encryptedbytes = cipher.doFinal(toencrypt.getBytes());
String encrypted = Base64.encodeBytes(encryptedbytes);
return encrypted;
}
}
修正:
The below corrections were applied.
(int i = 0; i < superSecretKeyBytes.length && i < key.length; i++)
Issue:
Array error has cleared but EditText string is still saved in clear text.?
为什么在循环条件下使用pass
长度,而周期内不使用长度?你确定superSecretKeyBytes.length == pass.length()
?(可能不等于,您正在从 Base64 解码)
这样写更安全:
for (int i = 0; i < superSecretKeyBytes.length; i++) {
key[i] = superSecretKeyBytes[i];
}
而不是:
for (int i = 0; i < pass.length(); i++) {
key[i] = superSecretKeyBytes[i];
}
另外,哪里可以保证您不会获得key
阵列的OutOfBoundsException
?更喜欢在循环中检查这一点:
for (int i = 0; i < superSecretKeyBytes.length && i < key.length; i++) {
key[i] = superSecretKeyBytes[i];
}
解码USERNAME_KEY时,看起来您引用了 pass.length 而不是 user.length 作为 for 循环中的停止条件,即以下第一个实例:
for (int i = 0; i < pass.length(); i++) {
应该是:
for (int i = 0; i < user.length(); i++) {
pass.length()(实际上它在技术上是 pass.length() - 1),大于在 key[] 和 superSecretKeyBytes[] 数组中分配的位置/位置。因此,您最终会尝试访问数组中不存在的位置,从而生成"越界"错误。
我认为你正在摆脱你的密钥数组。您应该检查:
pass.length() <= key.length
希望这有帮助