我正在尝试根据空格或某些符号(目前*_-<>
(拆分字符串。我将给出一些输入和输出的示例:
"Hello how are you" -> [ "Hello", " ", "how", " ", "are", " ", "you" ]
"Hello *how* are *you*" -> [ "Hello", " ", "*how*", " ", "are", " ", "*you*" ]
"Hello *how*are_you_" -> [ "Hello", " ", "*how*", "are", "_you_" ]
"*how*are _you_ *doing*_today_ hm?" -> [ "*how*", "are", " ", "_you_", " ", "*doing*", "_today_", " ", "hm?"
不幸的是,在空间上拆分会将像*how*_are_
这样的情况变成数组中的单个项目而不是多个项目。
我也尝试使用正则表达式进行拆分,但不幸的是,它没有保留每个单词周围的符号。
抱歉,如果这有点令人困惑。有没有处理这个问题的好方法?
与其使用split
,一种选择是使用.match
:匹配其中一个符号,后跟不是该符号的字符,然后再次匹配该符号,或者匹配非空格、非符号字符:
// Put the dash first, because it will be put into a character set:
const delims = '-*_<>';
// Construct a pattern like:
// ([-*_<>])(?:(?!1).)+1| |[^-*_<> ]+
const patternStr = String.raw
`([${delims}])(?:(?!1).)+1| |[^${delims} ]+`
const pattern = new RegExp(patternStr, 'g');
const doMatch = str => str.match(pattern);
console.log(doMatch("Hello how are you"));
console.log(doMatch("Hello *how*are_you_"));
console.log(doMatch("*how*are _you_ *doing*_today_ hm?"));
([-*_<>])(?:(?!1).)+1|[^-*_<> ]+
意味着:
([-*_<>])(?:(?!1).)+1
- 第一次交替:([-*_<>])
- 匹配和捕获初始分隔符(?:(?!1).)+
- 后跟任何不是初始分隔符的字符1
- 再次跟初始分隔符
s
第二次交替:匹配空格[^-*_<> ]+
- 第三次交替:匹配任何不是分隔符或空格的内容
尝试(这是改进的确定性能答案(
let split = s => s.match(/([-*_<>])(?:(?!1).)+1| |[^ ]+/g)
console.log(split("Hello how are you"));
console.log(split("Hello *how* are *you*"));
console.log(split("Hello *how*are_you_"));
console.log(split("*how*are _you_ *doing*_today_ hm?"));