如何根据Web服务的响应来禁用日期选择器的天数

Question

在我的项目中，有很多员工，每个员工都有自己的日程安排，我已经实施了一个网络服务，该服务返回了代表代表工作日的整数列表指定的员工，所有这些的主要思想是，我需要阻止用户在一周的其他日子中进行约会。或者如果还有另一种方法？

Web服务

[WebMethod]
    public void getWorkDays(int id)
    {
        WorkDays wd = new WorkDays(id);
        List<Days> workDays = new List<Days>();
        String docSch_query = "select * from workDays where empId = " + id + " and status=1";
        DBConnect conn = new DBConnect();
        DataTable dt = conn.select(docSch_query);
        foreach (DataRow r in dt.Rows)
        {
            switch (r["dayId"].ToString())
            {
                case "1":
                    workDays.Add(new Days(1,"sat"));
                    break;
                case "2":
                    workDays.Add(new Days(2, "sun"));
                    break;
                case "3":
                    workDays.Add(new Days(3, "mon"));
                    break;
                case "4":
                    workDays.Add(new Days(4, "tus"));
                    break;
                case "5":
                    workDays.Add(new Days(5, "wed"));
                    break;
                case "6":
                    workDays.Add(new Days(6, "thu"));
                    break;
            } 
        }
        JavaScriptSerializer js = new JavaScriptSerializer();
        Context.Response.Write(js.Serialize(workDays));           
    }

日期选择器

$(document).ready(function () {
        var dates=$.ajax({
            type: "POST",
            url: "getdays.asmx/getWorkDays",
            data: {id:<%#int.Parse(Session["appWith"].ToString())%>},
            dataType: "json",
            success: function (data) {
                return data.d;
            }
        });
        $('#edob').datepicker({
            firstDay: 3,
            beforeShowDay: function (date) {
                var available = $.inArray(date.getDay(), dates['int']) > -1;
                if (available) {
                    return [1];   //return available date
                }
                else {
                    return [0];   //return not available
                }
            }
        });
    })

Answer 1

我找到了问题的解决方案。

$(document).ready(function () {
        var dates = $.parseJSON(
            $.ajax({
                type: "POST",
                url: "getdays.asmx/getWorkDays",
                data: { id: <%=int.Parse(Session["appWith"].ToString())%> },
                dataType: "json",
                async: false
            }).responseText);
        $('#edob').datepicker({
            firstDay: 3,
            beforeShowDay: function (date) {
                var a =[];
                var weekend = false;
                for (i = 0; i < dates.length; i++) {
                    a.push(dates[i].Id);
                }
                var weekend = date.getDay() == 5 || date.getDay() == 6 || !($.inArray(date.getDay(),a)>-1);
                return [!weekend, weekend ? 'myweekend' : ''];
            }
      });
    });