在不追加的js文件中添加两个ajax

Question

我对这段代码有这个问题，我希望它附加到id中，但似乎不起作用请帮我

function getUrlParam(name) {
var results = new RegExp('[\?&]' + name + '=([^&#]*)').exec(window.location.href);
return (results && results[1]) || 'error';
}
var id = getUrlParam('user');
$(document).ready(function(){
var url = new URL(window.location.href);
var c = url.searchParams.get("user");
var loop_v;
var row_v;
var user_id = id;
$.ajax({  
url:"activity-post.php",  
type: 'post', 
data:{user:user_id},  
dataType: 'json',  
success:function(data)
{  
for (var i = 0; i < data.length; i++) {
$('#user_videos').append('<video class="video" playsinline controls><source src="'+data[i]+'" type="video/mp4" /></video>');
}
}
})
$.ajax({  
url:"activity-post.php",  
type: 'post', 
data:{user_files:user_id},  
dataType: 'json',  
success:function(response)
{  
alert(response.length);
for (var i = 0; i < response.length; i++) {
$('#user_media_mob').append('<div><img src="'response[i]'" class="img-fluid" alt="Responsive image"></div>');
}
}
})
})

但代码似乎不起作用，但如果我删除第二个ajax，它可以正常工作，但如果添加第二个ajax，到ajax将停止工作

这是我的php代码

session_start();
require('php-includes/connect.php');
require('php-includes/functions.php');
$user_img = array();
$user_data = array();
if (isset($_POST['user'])) {
if ($_POST['user'] == 'error') {
$user_id = $_SESSION['user_id'];
}else{
$user_id = mysqli_real_escape_string($con, test_input($_POST['user']));
}
$query = mysqli_query($con,"select * from post_media where user_id='$user_id' AND media_type='vid'");
if(mysqli_num_rows($query)>0){
$row_count = mysqli_num_rows($query);
$remain = $row_count%3;
while($row = $query->fetch_assoc()) {
if ($row["media_type"] == 'vid') {
array_push($user_img, $row["media_url"]);
}
}
}
echo json_encode($user_img);
}
if (isset($_POST['user_files'])) {
if ($_POST['user_files'] == 'error') {
$get_user_id = $_SESSION['user_id'];
}else{
$get_user_id = mysqli_real_escape_string($con, test_input($_POST['user_files']));
}
$query = mysqli_query($con,"select * from post_media where user_id='$get_user_id' AND media_type='img' OR media_type='doc'");
if(mysqli_num_rows($query)>0){
$row_count = mysqli_num_rows($query);
$remain = $row_count%3;
while($row = $query->fetch_assoc()) {
array_push($user_data, $row["media_url"]);
}
}
echo json_encode($user_data);
}

它意味着在给定的id中附加值，但根本没有响应

Answer 1

您的第二个ajax块包含语法错误(它缺少response[i]左右的+(：

更改：

$('#user_media_mob').append('<div><img src="'response[i]'" class="img-fluid" alt="Responsive image"></div>');

收件人：

$('#user_media_mob').append('<div><img src="'+response[i]+'" class="img-fluid" alt="Responsive image"></div>');