Symfony2原则一对一映射

Question

所以我试图在Symfony2中与Doctrine建立一对一的关系，但我得到以下错误:

在呈现模板期间抛出异常无法解析类的列"id"的类型"实体IntoPeople DatabaseBundle Feedbackcycle")IntoPeopleDatabaseBundle: Feedbackcycle: index . html。修改第65行

我有两个实体，Feedbackcycle和CDP。在反馈循环我有:

     /**
     * @var IntoPeopleDatabaseBundleEntityCdp
     *
     * @ORMOneToOne(targetEntity="IntoPeopleDatabaseBundleEntityCdp", inversedBy="feedbackcycle")
     * @ORMJoinColumns({
     *   @ORMJoinColumn(name="CDPId", referencedColumnName="Id")
     * })
     */
    private $cdp;

     /**
     * Set cdp
     *
     * @param IntoPeopleDatabaseBundleEntityCdp $cdp
     *
     * @return Feedbackcycle
     */
    public function setCdp(IntoPeopleDatabaseBundleEntityCdp $cdp = null)
    {
        $this->cdp = $cdp;
        return $this;
    }
    /**
     * Get cdp
     *
     * @return IntoPeopleDatabaseBundleEntityCdp
     */
    public function getCdp()
    {
        return $this->cdp;
    }

在CDP中我有:

     /**
     * @ORMOneToOne(targetEntity="Feedbackcycle")
     */
    protected $feedbackcycle;
     /**
     * Set feedbackcycle
     *
     * @param IntoPeopleDatabaseBundleEntityFeedbackcycle $feedbackcycle
     *
     * @return Cdp
     */
    public function setFeedbackcycle(IntoPeopleDatabaseBundleEntityFeedbackcycle $feedbackcycle = null)
    {
        $this->feedbackcycle = $feedbackcycle;
        return $this;
    }
    /**
     * Get feedbackcycle
     *
     * @return IntoPeopleDatabaseBundleEntityFeedbackcycle
     */
    public function getFeedbackcycle()
    {
        return $this->feedbackcycle;
    }

在我的分支中，我可以这样做:

{{ feedbackcycle.cdp.id }}

这将工作，或者我也可以做feedbackcycle。name(任何属性)它将工作。但是当我做

{{ feedbackcycle.cdp.*ANOTHER ATTRIBUTE* }}

Answer 1

解决了，我忘了在CDP中写mapappedby:

/**
 * @ORMOneToOne(targetEntity="Feedbackcycle", mappedBy="cdp")
 */
protected $feedbackcycle;