如何防止char输入影响int变量

Question

我有一个循环，它正在查找1到100之间的int。如果用户输入了一封信，循环就会变得疯狂。如何将字符和int分开？更多细节，更多细节，更详细，更多细节

#include<iostream>
#include<time.h>
using namespace std;
int main()
{   
const int GUESSES = 5;                // The user gets 5 guesses, that never changes
int randomNumber = -1;                // Initializing the random number
int guessesRemaining = GUESSES;       // Initializing the guesses remaining
int userGuess = -1;                   // Initializing the user guess variable
srand(time(0));                       // srand is using the time function to generate a random number
randomNumber = rand() % 100 + 1;      // rand is using the modulus operator to divide the ms by 100 then adds 1 to the solution
// original instructions for the user
cout << "Welcome to the number guessing game. The computer will select a number between 1";
cout << "and 100. It is your job to guess this secret number. You are allowed 5 guesses.nn";
do
{
    //cout << randomNumber;
    // user prompt
    cout << "Please enter a number between 1 and 100: ";
    // user input
    cin >> userGuess;
    // if the users guess is less than 100 and greater than 0
    if (userGuess < 100 && userGuess > 0)
    {
        // if user answers correctly
        if (userGuess == randomNumber)
        {
            switch (guessesRemaining)
            {
            case 5:
                cout << "nHoly crap! That's amazing! One shot, one kill!n";
                break;
            case 4:
                cout << "nWow, you're pretty good! You got it in two guesses!n";
                break;
            case 3:
                cout << "nNot bad. You got it in three guesses.n";
                break;
            case 2:
                cout << "nMan, that was a close one! You had one guess left.n";
                break;
            case 1:
                cout << "nBy the skin of your teeth! You got it on your last guess!!n";
                break;
            }
            break;
        }
        // if user does NOT answer correctly and still has guesses remaining
        else if (--guessesRemaining > 0 && userGuess != randomNumber)
        {
            // notifies user guess is too high and displays remaining guesses.
            if (userGuess > randomNumber)
            {
                cout << "nYour guess is too high, please try again. You have " << guessesRemaining << " guesses left.n";
            }
            // notifies user guess is too low and displays remaining guesses.
            else
            {
                cout << "nYour guess is too low, please try again. You have " << guessesRemaining << " guesses left.n";
            }
        }
    }
    // notifies user of invalid input.
    else
    {
        cout << "nDo you know how to read? Try again.n";
    }
} while (guessesRemaining > 0); // end of do/while loop, as long as remaing guesses are more than 0
// if user doesn't guess within the 5 guesses, notifies of loss and what winning number was.
if (guessesRemaining < 1)
{
    cout << "nWow, you suck. The number is " << randomNumber << endl << endl;
    system("pause");
    return 0;
}
system("pause");
return 0;

}

Answer 1

这可以通过简单地检查输入的值是否实际上是一个整数来实现，然后再将其用作一。由于你还没有提供一种语言，一般的想法是…

Read input into X
Check that X is in fact an integer (atoi, etc)
Use the value of X as an integer, most likely in another variable