"TypeError: object of type 'Response' has no len()"

Question

当我尝试执行代码时

BeautifulSoup(html, ...)

它给出错误信息

TypeError:"Response"类型的对象没有len（）

我尝试将实际的HTML作为参数传递，但它仍然不起作用。

import requests
url = 'http://vineoftheday.com/?order_by=rating'
response = requests.get(url)
html = response.content
soup = BeautifulSoup(html, "html.parser")

Answer 1

您得到的是response.content。但它以字节（docs）的形式返回响应体。但是您应该将str传递给BeautifulSoup构造函数（docs）。因此，您需要使用response.text，而不是获取内容。

Answer 2

尝试直接传递HTML文本

soup = BeautifulSoup(html.text)

Answer 3

html.parser用于忽略页面中的警告：

soup = BeautifulSoup(html.text, "html.parser")

Answer 4

如果使用requests.get('https://example.com')获取HTML，则应该使用requests.get('https://example.com').text。

Answer 5

您在"response"中只得到响应代码并始终使用浏览器标头以确保安全，否则你将面临许多问题

在调试器控制台网络部分"header"UserAgent 中查找标头

尝试

import requests
from bs4 import BeautifulSoup
from fake_useragent import UserAgent
url = 'http://www.google.com'
headers = {'User-Agent': 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_13_6) 
AppleWebKit/537.36 (KHTML, like Gecko) Chrome/71.0.3578.98 Safari/537.36'}
response = requests.get(quote_page, headers=headers).text
soup = BeautifulSoup(response, 'html.parser')
print(soup.prettify())

Answer 6

from bs4 import BeautifulSoup
import requests

url = 'your_url'
response = requests.get(url)
html = response.content
soup = BeautifulSoup(html, "html.parser")
print(soup)

Answer 7

它对我有效：

soup = BeautifulSoup(requests.get("your_url").text)

现在，下面的代码更好了（使用lxml解析器）：

import requests
from bs4 import BeautifulSoup
soup = BeautifulSoup(requests.get("your_url").text, 'lxml')

Answer 8

您应该使用.text来获取响应的内容

import  requests
url = 'http://www ... '
response = requests.get(url)
print(response.text)

或与肥皂一起使用

import  requests
from bs4 import BeautifulSoup
url = 'http://www ... '
response = requests.get(url)
msg = response.text
print(BeautifulSoup(msg,'html.parser'))

Answer 9

import requests
from urllib.request import urlopen
from bs4 import BeautifulSoup
import re
url = "https://fortnitetracker.com/profile/all/DakshRungta123"
html = requests.get(url)
soup = BeautifulSoup(html)

title = soup.text
print(title.text)

Answer 10

import requests
url = 'http://vineoftheday.com/?order_by=rating'
response = requests.get(url)
html = response.content
soup = BeautifulSoup(html.text, "html.parser")