为什么我得到 Json 的结构而不仅仅是值?

Question

我认为已经了解如何获取具有不同特征的 Json 数据 此 JSON 的括号。使用我的代码，我获得了我需要的数据，但我注意到两件事。

1(为什么我不能通过getText((指定我需要距离的文本值，因为当我编写代码时，只需让我在getElements((中。

2(为什么如果我显示距离的值，它给了我所有从元素开始的Json结构，例如：[元素{距离=距离{文本='5.6km'}}]，而不仅仅是5.6Km

持续时间也是如此！

Retrofit retrofit = new Retrofit.Builder()
.baseUrl("https://maps.googleapis.com")
.addConverterFactory(GsonConverterFactory.create())
.build();
ApiInterface apiInterface = retrofit.create(ApiInterface.class);
Call<Feed> call = apiInterface.getData();
call.enqueue(new Callback<Feed>() {
@Override
public void onResponse(Call<Feed> call, Response<Feed> response) {
Log.d(TAG, "onResponse: Server Response: "+response.toString());
Log.d(TAG, "onResponse: received information: "+ response.body().toString());
ArrayList<Rows> rowsList = response.body().getRows();
ArrayList<String> destination_addresses_list = response.body().getDestination_addresses();
for (int i=0; i<rowsList.size(); i++){

Log.d(TAG, "onResponse: n"+
"destination_addresses: "+ destination_addresses_list.get(i)+"n"+
// this is where I cant specify getElements().getDistance().getText()
"distance"+ rowsList.get(i).getElements()+
//And in this one too!  getElements().getDuration().getText()
"duration"+ rowsList.get(i).getElements());
}
}
@Override
public void onFailure(Call<Feed> call, Throwable t) {
Log.e(TAG, "onFailure: algo paso: "+ t.getMessage());
Toast.makeText(getApplicationContext(), "error", Toast.LENGTH_LONG).show();
}
});

饲料类别：

public class Feed {

@SerializedName("destination_addresses")
@Expose
private ArrayList<String> destination_addresses;
// este contiene cas datos que se pueden separar
@SerializedName("rows")
@Expose
private ArrayList<Rows> rows;

public ArrayList<String> getDestination_addresses() {
return destination_addresses;
}
public void setDestination_addresses(ArrayList<String> destination_addresses) {
this.destination_addresses = destination_addresses;
}
public ArrayList<Rows> getRows() {
return rows;
}
public void setRows(ArrayList<Rows> rows) {
this.rows = rows;
}
@Override
public String toString() {
return "Feed{" +
"destination_addresses=" + destination_addresses +
", rows=" + rows +
'}';
}
}

行类

public class Rows {
@SerializedName("elements")
@Expose
private ArrayList<Elements> elements;
public ArrayList<Elements> getElements() {
return elements;
}
public void setElements(ArrayList<Elements> elements) {
this.elements = elements;
}
@Override
public String toString() {
return "Rows{" +
"elements=" + elements +
'}';
}
}

元素类

public class Elements {
@SerializedName("distance")
@Expose
private Distance distance;

@SerializedName("duration")
@Expose
private Duration duration;

public Distance getDistance() {
return distance;
}
public void setDistance(Distance distance) {
this.distance = distance;
}

public Duration getDuration() {
return duration;
}
public void setDuration(Duration duration) {
this.duration = duration;
}

@Override
public String toString() {
return "Elements{" +
"distance=" + distance +
//  ", duration=" + duration +
'}';
}
}

距离等级

public class Distance {
@SerializedName("text")
@Expose
private String text;

public String getText() {
return text;
}
public void setText(String text) {
this.text = text;
}

@Override
public String toString() {
return "Distance{" +
"text='" + text + ''' +
'}';
}
}

持续时间类

public class Duration {

@SerializedName("text")
@Expose
private String text;
public String getText() {
return text;
}
public void setText(String text) {
this.text = text;
}

@Override
public String toString() {
return "Duration{" +
"text='" + text + ''' +
'}';
}
}

Answer 1

getElements().返回元素数组列表，所以你不能只说

getElements().getDuration().getText() 

您必须指定尝试在 JSON 中访问的元素的位置，它只是一个元素，因此正确的格式是

getElements().get(0).getDuration().getText()

或者，如果有多个元素，您可以按索引查看元素

而且，如果您在 JSON 处循环，它会返回 JSON 数组而不是 JSON 对象