将网络电量与单声道和通量相结合的问题

Question

嗨，我有助焊剂，在每个元素上都创建新的单声道。我还在磁通范围外还有其他单声道。并想执行以下操作：当磁通(带有相应的内部单声道的末端(时，请执行第二个单声道。Challegeing Prart是Mono内部的磁通量是根据WebClient请求创建的。作为起点，请查看"负载"方法。 基本上没有网络电量，它可以正常工作，但是在此之后使用WebClient内部地图工作。 使用Spring-boot 2

public WebClient.ResponseSpec sendGetRequest(String path, Object... pathVariables){
   try {
       LOGGER.info("content type {}, url {}, path {}", contentType, url, path);
       WebClient.ResponseSpec responseSpec = sendRequest(HttpMethod.GET, contentType, authorizationToken, url, path, pathVariables);
       return responseSpec;
   }catch (Exception e){
       throw new WebClientProcessingException("Exception when trying to process", e);
   }
}
public Mono<PersonPayload> loadPerson(String  path){
    try {
        LOGGER.info("path {}", path);
        Mono<QuestionDetailsPayload> person = sendGetRequest(path).bodyToMono(PersonPayload.class);
        return person;
    }catch (Exception e){
        throw new WebClientProcessingException("Exception when trying to process",e);
    }
}

public Mono<PersonDomain> getPerson(String path) {
    Assert.notNull(path, "path can't be null");
    try{
        LOGGER.info("path {}" ,path);
        Mono<PersonPayload> personPayload = loadPerson(path);
        return personPayload.map(this::toPersonDomain);
    }catch (Exception e){
        throw new PersonNotFoundException("Exception when trying to get person info" , e);
    }
}
public PersponDomain toPersonDomain(PersonPayload personPayload){
    return modelMapper.map(personPayload, PersonDomain.class);
}
public void load(){
    List<String> outStr = Arrays.asList("out1", "out2","out3");
    Flux flux = Flux.fromIterable(outStr);
    Flux<Mono<PersonDomain>> results =  flux.map(string ->{
        System.out.println(string);
        Mono<PersonDomain> personMono = getPerson("inside");
        Mono<String> result = personMono.map(h ->{
            System.out.println(personMono.getName());
            return personMono.getName() + "_test";
        });
        return result;
    });
    Mono<String> second = Mono.just("second");
    results.then(second);
    results.subscribe(stringMono -> {
        stringMono.subscribe();
    });
    second.subscribe( s->{
        System.out.println(s);
    });
}

gradle依赖性：

implementation 'org.springframework.boot:spring-boot-starter-webflux'
implementation 'org.springframework.boot:spring-boot-starter-validation'
implementation 'org.postgresql:postgresql'
implementation 'org.springframework.boot:spring-boot-starter-jooq'
implementation 'org.jooq:jooq-codegen'
implementation 'org.modelmapper:modelmapper:2.3.0'
implementation 'org.modelmapper:modelmapper:2.3.0'
compileOnly 'org.projectlombok:lombok'
annotationProcessor 'org.projectlombok:lombok'
implementation 'com.google.code.gson:gson:2.8.5'
testImplementation 'org.springframework.boot:spring-boot-starter-test'
testImplementation 'io.projectreactor:reactor-test'
testImplementation 'org.powermock:powermock-module-junit4:2.0.0'
testImplementation 'org.powermock:powermock-api-mockito2:2.0.0'}

Answer 1

Flux#map是同步操作，不订阅返回的对象。

您应该使用Flux#flatMap/Flux#concatMap/Flux#flatMapSequential/Flux#switchMap。这些操作员将订阅返回的Publisher。

Answer 2

解决我的情况的解决方案使用：

subscribe(Consumer<? super T> consumer,
          Consumer<? super Throwable> errorConsumer,
          Runnable completeConsumer); 

而不是这样。处理值和错误，但在序列成功完成后也执行一些代码。