我每次尝试使用 Python 将列表旋转两个

Question

我写了一个代码，用户输入一个代码，程序会按所需的量旋转它，但每次都会旋转两个而不是一个。 例如，1 2 3 4 5 旋转一将变为 4 5 1 2 3 我的代码是：

arSize = int(input("Please enter the size of the list "))
arr = []
d = int(input("How many times do you want to rotate it to the right? :"))
for i in range(0, arSize) :
number = int(input("Please enter array[" + str(i) + "] value: "))
arr.append(number)
n = arSize
def rightRotate(arr, d, n): 
for i in range(d): 
rightRotatebyTwo(arr, n) 
def rightRotatebyTwo(arr, n):
temp = arr[0]
temp1 = arr[1]
arr[1] = arr[n-1]
arr[0] = arr[n-2]
for i in range(2, n-1):
temp2 = arr[i]
temp3 = arr[i+1]
arr[i] = temp
arr[i+1] = temp1
temp = temp1
temp1 = temp2

def printArray(arr, size): 
for i in range(size): 
print (arr[i]) 
rightRotate(arr, d, n) 
printArray(arr, n)

结果如下：

Please enter the size of the list 6
How many times do you want to rotate it to the right? :1
Please enter array[0] value: 1
Please enter array[1] value: 2
Please enter array[2] value: 3
Please enter array[3] value: 4
Please enter array[4] value: 5
Please enter array[5] value: 6
5
6
1
2
3
2

Answer 1

你的方法有点太复杂了。您应该尝试不同的方法。

例如： 一个简单的切片操作在这里就可以了。

def rotateRight(no_of_rotations):
arr = [1, 2, 3, 4, 5] 
arr = arr[no_of_rotations:] + arr[:no_of_rotations] 
return arr 

万事如意！:)