这是计算唯一身份访问者的好方法吗?

Question

<?php
$date = date("Y-m-d"); //Return current date in yyyy-mm-dd format
$userIP = $_SERVER['REMOTE_ADDR'];// Stores remote user ip address
$query = "SELECT * FROM `unique_visitors` WHERE `date` = '$date'";
$result = mysqli_query($connection,$query);
if($result->num_rows == 0)// this block will execute when there is no record of current date in database
{
$insertQuery = "INSERT INTO `unique_visitors` (`date`,`ip`) VALUES ('$date','$userIP')";
mysqli_query($connection,$insertQuery);
}
else
{
$row = $result->fetch_assoc();//Extracts result row from result object
if(!preg_match('/'.$userIP.'/i',$row['ip']))//Will execute When Current ip is not in databse
{
$newIP = "$row[ip] $userIP"; //Combine previous and current user ip address with a separator for updating in database
$updateQuery = "UPDATE `unique_visitors` SET `ip`='$newIP', `views`=`views`+1 WHERE `date` = '$date' ";
mysqli_query($connection,$updateQuery);
}
}
?>

有没有更好的方法来计算我网站中的唯一身份访问者，或者这个简单的代码可以插入到我的网站中？

Answer 1

这是您采用的方法的基本 PHP/mysqli 代码。您必须为两个字段(日期和 ip(创建一个唯一索引。一切都只需一个查询即可工作。

<?php
$userIP = $_SERVER['REMOTE_ADDR'];// Stores remote user ip address
$sql = "INSERT INTO unique_visitors (date, ip, views) VALUES (curdate(),?,1)
ON DUPLICATE KEY UPDATE views = views + 1";
$stmt = $connection->prepare($sql);
$stmt->bind_param("s", $userIP);
$stmt->execute();
$sql = "SELECT count(*) FROM unique_visitors WHERE date = curdate()";
$result = $connection->query($sql);
$visitors = $result->fetch_row()[0];