rubyzip:打开zip，临时修改，发送到客户端

Question

我想临时修改一个zip文件，并将更改后的文件发送到客户端。

现在我创建一个文件流并发送它：

require 'zip'
zip_stream = Zip::OutputStream.write_buffer do |zip|
zip.put_next_entry 'new_folder/file'
zip.print "some text"
end
zip_stream.rewind
send_data zip_stream.read, type: 'application/zip', disposition: 'attachment', filename: 'thing.zip'

我不知道如何在文件系统中打开一个现有的zip，并在其中放入额外的文件，然后在不保存到磁盘的情况下发送它。

你能给我一个提示吗？

Answer 1

最后我这样做了：

require 'zip'
zip_stream = Zip::OutputStream.write_buffer do |new_zip|
existing_zip = Zip::File.open('existing.zip')
existing_zip.entries.each do |e|
new_zip.put_next_entry(e.name)
new_zip.write e.get_input_stream.read
end
new_zip.put_next_entry 'new_file'
new_zip.print "text"
end

Answer 2

检查此项https://github.com/rubyzip/rubyzip

require 'rubygems'
require 'zip'
folder = "Users/me/Desktop/stuff_to_zip"
input_filenames = ['image.jpg', 'description.txt', 'stats.csv']
zipfile_name = "/Users/me/Desktop/archive.zip"
Zip::File.open(zipfile_name, Zip::File::CREATE) do |zipfile|
input_filenames.each do |filename|
# Two arguments:
# - The name of the file as it will appear in the archive
# - The original file, including the path to find it
zipfile.add(filename, File.join(folder, filename))
end
zipfile.get_output_stream("myFile") { |f| f.write "myFile contains just this" }
end