嗨，我对bash脚本有点陌生，在编写自己的脚本时不是很专业，我有一个可以在终端中完美工作的脚本。我想用zenity让事情变得简单明了（但也作为一个小的学习项目）。
该脚本生成随机密码，使用zenity是一个很好的小工具。
不过，我遇到了一个问题，该脚本作为GUI运行得很好，但当我想为用户引入一种选择密码长度的方法时，它无法生成密码。让用户输入所需号码（密码长度）的代码：
number=32
zenity --entry --text="Please enter a number (no limitations!) :" --entry-text="$number"
read newnumber
[ -n "$newnumber" ] && number=$newnumber
如果在终端中运行，则显示在终端中输入的数字，但不显示在zenity框中。我不能使用变量…：
number=$newnumber
在脚本的后面，我根据需要更改了一个变量：
LENGTH="32"
收件人：
LENGTH="$newnumber"
脚本作为GUI正常运行（除了不生成密码），但在我得到的终端中（如果用户输入了数字25）：
25
/home/server/Desktop/passwd32gen: line 22: [: : integer expression expected
因此，我使用$newnumber作为LENGTH=变量中的值，破坏了脚本的生成部分。我自己尝试了各种不同的方法来解决这个问题，但知道的太多了，我认为这将是一个非常简单的语法缺失部分（或者我只是希望如此）。
现在我已经无计可施了，我试过
declare
和
eval
在很多方面，但他们似乎只是打破了剧本。
提前感谢任何可以帮忙的人！
请记住，我正在寻找一种使用zenity的方法，允许用户选择正在生成的密码的长度。
整个脚本是：
#!/bin/bash
# May need to be invoked with #!/bin/bash2 on older machines.
#
#Random 32 character password generator
#
zenity --info --title="32 Character Password Generator" --text="Hi, so you want to get yourself a new password? You've the perfect little application here, just click OK to generate your new password."
number=32
zenity --entry --text="Please enter a number (no limitations!) :" --entry-text="$number"
read newnumber
[ -n "$newnumber" ] && number=$newnumber
MATRIX="0123456789<?/_+-!@#$%^&*>ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz"
# Password will consist of standard characters.
LENGTH="$newnumber"
#This variable can be changed for password lenth (need to try get zenity to let user choose that number)
while [ "${n:=1}" -le "$LENGTH" ]
# := is "default substitution" operator.
# So, if 'n' has not been initialized, set it to 1.
do
PASS="$PASS${MATRIX:$(($RANDOM%${#MATRIX})):1}"
# Very clever, but tricky.
# Starting from the innermost nesting...
# ${#MATRIX} returns length of array MATRIX.
# $RANDOM%${#MATRIX} returns random number between 1
# and [length of MATRIX] - 1.
# ${MATRIX:$(($RANDOM%${#MATRIX})):1}
# returns expansion of MATRIX at random position, by length 1.
# See {var:pos:len} parameter substitution in Chapter 9.
# and the associated examples.
# PASS=... simply pastes this result onto previous PASS (concatenation).
# to let zenity show the password being built one character at a time, uncomment the following line
# zenity --info --text="$PASS"
let n+=1
# Increment 'n' for next pass.
done
zenity --info --title="Your 32 character password" --text="Here is your random 32 character password, you can copy and paste it wherever you wish...
$PASS
The passwords generated by this application are very strong, here are the numbers;
Length: 32 characters
Character Combinations: 96
Calculations Per Second: 4 billion
Possible Combinations: 2 vigintillion
Based on an average Desktop PC making about 4 Billion calculations per second
It would take about 21 quattuordecillion years to crack your password.
As a number that's 21,454,815,022,336,020,000,000,000,000,000,000,000,000,000,000 years!" # you could redirect to a file, to store the password. Use something like $PASS 2> /file/name
exit 0
zenity命令后面的read命令不会从zenity读取，它仍然像往常一样从stdin读取。
相反，你可能想要：
newnumber=$(zenity --entry
--text="Please enter a number (no limitations!) :"
--entry-text="$number")
不需要以下CCD_ 4命令。
也就是说，如果你确实出于某种原因想要使用read，你仍然可以这样做：
read -r newnumber < <(zenity --entry
--text="Please enter a number (no limitations!) :"
--entry-text="$number")
如果你真的想显示特殊字符，你可以使用zenity——文本信息，如下所示。它在美学上不那么令人愉悦，但它是可以做到的。
只需2美分
echo "Here is your random $newnumber character password, you can copy and paste it wherever you wish...
$PASS
The passwords generated by this application are very strong, here are the numbers;
Length: $newnumber characters
Character Combinations: 96
Calculations Per Second: 4 billion
Possible Combinations: 2 vigintillion
Based on an average Desktop PC making about 4 Billion calculations per second
It would take about 21 quattuordecillion years to crack your password.
As a number that's 21,454,815,022,336,020,000,000,000,000,000,000,000,000,000,000 years!" | zenity --text-info --title "Your $newnumber character password" --width 600 --height 500`
附录
在玩了更多之后，zenity似乎不喜欢打印带有特殊字符的变量。
这个脚本应该可以工作
我做了两个改动。
1 newnumber=` zenity。。。。这将读取zenity的输入。
2从矩阵中删除了一些特殊字符
我用#CHANGED 标记了所有更改
这是修改后的剧本。
#!/bin/bash
# May need to be invoked with #!/bin/bash2 on older machines.
#
#Random 32 character password generator
#
zenity --info --title="32 Character Password Generator" --text="Hi, so you want to get yourself a new password? You've the perfect little application here, just click OK to generate your new password."
number=32
# CHANGED
newnumber=`zenity --entry --text="Please enter a number (no limitations!) :" --entry-text="$number"`
# read newnumber
[ -n "$newnumber" ] && number=$newnumber
#CHANGED Removed offending special characters
MATRIX="0123456789?_+-!$%^>ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz"
# Password will consist of standard characters.
LENGTH="$newnumber"
#This variable can be changed for password lenth
#(need to try get zenity to let user choose that number)
while [ "${n:=1}" -le "$LENGTH" ]
# := is "default substitution" operator.
# So, if 'n' has not been initialized, set it to 1.
do
PASS="$PASS${MATRIX:$(($RANDOM%${#MATRIX})):1}"
# Very clever, but tricky.
# Starting from the innermost nesting...
# ${#MATRIX} returns length of array MATRIX.
# $RANDOM%${#MATRIX} returns random number between 1
# and [length of MATRIX] - 1.
# ${MATRIX:$(($RANDOM%${#MATRIX})):1}
# returns expansion of MATRIX at random position, by length 1.
# See {var:pos:len} parameter substitution in Chapter 9.
# and the associated examples.
# PASS=... simply pastes this result onto previous PASS (concatenation).
# to let zenity show the password being built one character at a time, uncomment the following line
# zenity --info --text="$PASS"
let n+=1
# Increment 'n' for next pass.
done
# CHANGED $PASS to '$PASS' below
zenity --info --title="Your 32 character password" --text="Here is your random 32 character password, you can copy and paste it wherever you wish...
$PASS
The passwords generated by this application are very strong, here are the numbers;
Length: 32 characters
Character Combinations: 96
Calculations Per Second: 4 billion
Possible Combinations: 2 vigintillion
Based on an average Desktop PC making about 4 Billion calculations per second
It would take about 21 quattuordecillion years to crack your password.
As a number that's 21,454,815,022,336,020,000,000,000,000,000,000,000,000,000,000 years!" # you could redirect to a file, to store the password. Use something like $PASS 2> /file/name
exit 0