我想将字符串列表转换为小写并在保留顺序的同时删除重复项。我在StackOverflow上发现的许多单行Python魔力将字符串列表转换为小写,但似乎顺序丢失了。
我已经编写了下面的代码,它实际上有效,我很高兴坚持下去。但我想知道是否有一种方法可以做到这一点,它更 pythonic 和更少的代码(如果我将来要写类似的东西,可能会更少错误。这个花了我相当长的时间才写出来)。
def word_list_to_lower(words):
""" takes a word list with a special order (e.g. frequency)
returns a new word list all in lower case with no uniques but preserving order"""
print("word_list_to_lower")
# save orders in a dict
orders = dict()
for i in range(len(words)):
wl = words[i].lower()
# save index of first occurence of the word (prioritizing top value)
if wl not in orders:
orders[wl] = i
# contains unique lower case words, but in wrong order
words_unique = list(set(map(str.lower, words)))
# reconstruct sparse list in correct order
words_lower = [''] * len(words)
for w in words_unique:
i = orders[w]
words_lower[i] = w
# remove blank entries
words_lower = [s for s in words_lower if s!='']
return words_lower
稍微修改答案 如何在保持顺序的同时从列表中删除重复项?
def f7(seq):
seen = set()
seen_add = seen.add
seq = (x.lower() for x in seq)
return [x for x in seq if not (x in seen or seen_add(x))]
你也可以做:
pip install orderedset
然后:
from orderedset import OrderedSet
initial_list = ['ONE','one','TWO','two','THREE','three']
unique_list = [x.lower() for x in list(OrderedSet(initial_list))]
print unique_list
只需执行以下操作:
initial_list = ['ONE','one','TWO','two']
uninique_list = [x.lower() for x in list(set(initial_list))]
print unique_list
initial_list = ['ONE','one','TWO','two']
new_list = []
[new_list.append(s.lower()) for s in initial_list if s.lower() not in new_list]