C语言 如果我发现列表以任何中间点入气泡排序,如何停止我的进程


#inlcude<stdio.h>
int main()
{
 int arr[30],num,i,j,k,temp,l=0;
 printf("Enter the number of elements :n");
 scanf("%d",&num);
 for(i=1;i<=num;i++)
 {
   printf("Enter element %dn",i);
   scanf("%d",&arr[i]);
 }
for(k=1;k<=num;k++)
{if(arr[k]>arr[k+1])
  l++;}
 if(l!=0)
 {   
 for(i=2;i<=num;i++)
 {l=0;
   for(k=1;k<=num;k++)
   {
     if(arr[k]>arrk+1])
     l++;}
   if(l!=0)
   {for(j=1;j<num;j++)
    {
     if(arr[j]>arr[j+1])
     {
       temp=arr[j];
       arr[j]=arr[j+1];
       arr[j+1]=temp;
     }
    }
  printf("nAfter pass %d elements are:",i-1);
  for(k=1;k<=num;k++)
     printf("%d",arr[k]);}
  else
     break;
     }
  }
  printf("nsorted list is:n");
  for(k=1;k<=num;k++)
     printf("%d ",arr[k]);
   retrun 0;
 }

这是气泡排序程序。我的查询是,如果我发现我的列表在任何中间点排序,我需要停止我的进程。我什至做到了...但是这个程序仍然存在一些问题。它未在门户中被接受,它会触发,因为程序是"错误答案"。我想在找出中间点时可能存在错误。帮我弄清楚这一点..

您可以设置一个标志并检查列表是否按如下方式排序:

for(i=0; i ......
{
flag=1; // We are setting a "break point" here by setting flag=1; If any exchange of elements take place inside if loop, flag will be
//set back to zero inside the if block statements.
for(j=0; j ......
{
if (a[j]>a[j+1])
{
temp=a[j];
a[j]=a[j+1];
a[j+1]=temp;
flag=0; // flag is set back to zero because there occured an "exchange of element"
}
}
}
#include<stdio.h>
int main() 
{
  int array[100],i,n,c,swap,flag=0;
  printf("Enter the number of elements :n");
  scanf("%d",&n);
  for(c=0;c<n;c++)
  {
  printf("Enter element %dn",c+1);
  scanf("%d",&array[c]);
  }
  printf("Unsorted list is :n");
  for(i=0;i<n;i++)
    printf("%d ",array[i]);
  printf("n");
  for(c=0;c<n-1;c++)
  {
    if(flag==0)
    {
      flag=1;
     for(i=0;i<n-1;i++)
     { 
        if(array[i]>array[i+1])
        {
          swap=array[i];
          array[i]=array[i+1];
          array[i+1]=swap;
          flag=0;
        }
    }
    printf("After Pass %d elements are :",c+1);
    for(i=0;i<n;i++)
    {
      printf("%d ",array[i]);
    }                   
    printf("n");
    }
  }
  printf("Sorted list is :n");
  for(c=0;c<n;c++)
    printf("%d ",array[c]);
  return 0;
}

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