无法在函数之间传递变量中的数据

Question

我对Python相当陌生。我熟悉跨函数传递数据的概念。

理论上，

def c():
   r = raw_input("Ask Something? ")
   ..
   return r
def p(x):
    ...
    do something
r = c()
p(r)

下面的代码通过终端(python filename.py 文件.txt(工作得很好，但我想添加工作流，其中变量存储文件的路径并将其传递给函数(进程文件(。我只是无法获取传递给函数的数据/值。

这是我正在尝试编辑的代码：

def registerException(exc):
    exceptions[exc] += 1
def processFile(x):
  with open(x, "r") as fh:
    currentMatch = None
    lastLine = None
    addNextLine = False
    for line in fh.readlines():
      if addNextLine and currentMatch != None:
         addNextLine = False
         currentMatch += line
         continue
      match = REGEX.search(line) != None
      if match and currentMatch != None:
         currentMatch += line
      elif match:
         currentMatch = lastLine + line
      else:
         if currentMatch != None:
            registerException(currentMatch)
         currentMatch = None
      lastLine = line
      addNextLine = CONT.search(line) != None
    # If last line in file was a stack trace
    if currentMatch != None:
      registerException(currentMatch)
for f in sys.argv[1:]:
  processFile(f)
for item in sorted(exceptions.items(), key=lambda e: e[1], reverse=True):
  print item[1], ":", item[0]

我将变量声明为全局变量还是局部变量并不重要。有人可以帮我解决这个问题吗？

编辑 1 ：

我已经应用了丹尼尔建议的更改，现在我得到：类型错误："NoneType"对象不可迭代。

下面是代码：

def c():
    path = raw_input("Path to file? ")
    r = os.path.abspath(path)
def process_file(filename):
    current = None
    last_line = None
    continue_line = False
    with open(filename, "r") as fh:
        for line in fh:
            if continue_line and current is not None:
               continue_line = False
               current += line
               continue
            if REGEX.search(line):
               if current is None:
                  current = last_line
               current += line
            else:
               if current is not None:
                  yield current
               current = None
            last_line = line
            continue_line = CONT.search(line)
        # If last line in file was a stack trace
        if current is not None:
            yield current
def process_files(filenames):
    exceptions = defaultdict(int)
    for filename in filenames:
        for exc in process_file(filename):
            exceptions[exc] += 1
for item in sorted(exceptions.items(), key=lambda e: e[1], reverse=True):
    print item[1], ":", item[0]
r = c()
process_files(r)

我做了一些更改并删除了sys.argv[1]，因为它在运行脚本时需要在命令行中有一个参数。

我认为我得到的新错误是由于操作系统路径造成的。我该如何解决这个问题？

Answer 1

exceptions也是一个参数，必须传递给所有函数。或者，您可以将processFile编写为生成器，内联registerException：

def process_file(filename):
    current = None
    last_line = None
    continue_line = False
    with open(filename, "r") as fh:
        for line in fh:
            if continue_line and current is not None:
                continue_line = False
                current += line
                continue
            if REGEX.search(line):
                if current is None:
                    current = last_line
                current += line
            else:
                if current is not None:
                    yield current
                current = None
            last_line = line
            continue_line = CONT.search(line)
        # If last line in file was a stack trace
        if current is not None:
            yield current
def process_files(filenames)
    exceptions = defaultdict(int)
    for filename in filenames:
        for exc in process_file(filename):
            exceptions[exc] += 1
    for item in sorted(exceptions.items(), key=lambda e: e[1], reverse=True):
        print item[1], ":", item[0]
process_files(sys.argv[1:])