如何返回Spring ExceptionHandler
类中的List<DataStruture>
错误代码?我尝试了以下代码:
@ExceptionHandler({ CustomException.class })
@ResponseStatus(HttpStatus.CONFLICT)
public List<ErrorOutDTO> handle(CustomException theException) {
return new null;
}
我被方法的返回类型击中。
您应该绑定响应性中的错误列表,然后返回。
@ExceptionHandler(CustomException.class)
public ResponseEntity<List<ErrorOutDTO>> validationExceptionHandler(CustomException exception) {
List<ErrorOutDTO> list = new ArrayList<>();
ErrorOutDTO error = new ErrorOutDTO();
error.setField(exception.getField());
error.setMessage(exception.getMessage());
list.add(error);
return (ResponseEntity<List<ErrorOutDTO>>)new ResponseEntity(list, HttpStatus.CONFLICT);
}
例如,如果异常是CondainVioLationException:此异常报告约束违规的结果
@ExceptionHandler({ ConstraintViolationException.class })
public ResponseEntity<Object> handleConstraintViolation(
ConstraintViolationException ex, WebRequest request) {
List<String> errors = new ArrayList<String>();
for (ConstraintViolation<?> violation : ex.getConstraintViolations()) {
errors.add(violation.getRootBeanClass().getName() + " " +
violation.getPropertyPath() + ": " + violation.getMessage());
}
ApiError apiError =
new ApiError(HttpStatus.BAD_REQUEST, ex.getLocalizedMessage(), errors);
return new ResponseEntity<Object>(
apiError, new HttpHeaders(), apiError.getStatus());
}