在python中调用dll时传递的值出错

Question

我有不同的dll导出这个函数(一个函数每个dll):

dll1:

DECLDIR void getFrameworkVersion(int* pMajor, int* pMinor, int* pBugfix);

dll2:

void __stdcall getFrameworkVersion(int* pMajor, int* pMinor, int* pBugfix);

我在python中导入这两个dll没有错误，调用它们也没有错误。然而，我得到错误的值

dll1 = cdll.LoadLibrary('dll1')
dll2 = oledll.LoadLibrary('dll2')
pMajor = pMinor = pbugFix = c_int()
dll1.getASTFrameworkVersion.argtypes = [ctypes.POINTER(ctypes.c_int), ctypes.POINTER(ctypes.c_int), ctypes.POINTER(ctypes.c_int)]
#test.eval.restype = ctypes.c_double
dll1.getASTFrameworkVersion(byref(pMajor), byref(pMinor), byref(pbugFix))
astVersion = "AST Framework version: " + str(pMinor.value) + "."  + str(pbugFix.value) + "."  + str(pMajor.value)
dll2.getFrameworkVersion.argtypes = [ctypes.POINTER(ctypes.c_int), ctypes.POINTER(ctypes.c_int), ctypes.POINTER(ctypes.c_int)]
dll2.getFrameworkVersion(byref(pMajor), byref(pMinor), byref(pbugFix))
asfVersion = "ASF Framework version: " + str(pMinor.value) + "."  + str(pbugFix.value) + "."  + str(pMajor.value)

我得到这样的输出:

    AST Framework version: 0.0.0
    ASF Framework version: 14.14.14

Answer 1

pMajor = pMinor = bugFix = c_int()是错误的:所有三个Python名称都是相同的c_int实例，因此将包含相同的值!你所做的等同于C中的以下代码:

int x;
getFrameworkVersion(&x, &x, &x);

所以你得到0.0.0的事实可能是因为真正的结果将在.0结束，它覆盖了前面的两个值。