如何对hibernate投影结果应用顺序

Question

我使用了以下休眠条件。

Criteria criteria = session.createCriteria(Student.class);
        ProjectionList projectionList = Projections.projectionList();
       projectionList.add(Projections.groupProperty("studentId"));
       projectionList.add(Projections.count("studentId"));
        criteria.setProjection(projectionList);
      return criteria.list();

这返回一个对象列表，对象有两个字段，studentId和count（studentId）。我想按从（studentId）递减的计数对这个列表进行排序。我该如何冬眠？

目前我正在接受

{[1, 5], [2, 7], [3,4]} 

我想买这个

{[2, 7], [1, 5], [3,4]}

解决方案：这解决了问题：）

  Criteria criteria = session.createCriteria(Student.class);
            ProjectionList projectionList = Projections.projectionList();
           projectionList.add(Projections.groupProperty("studentId"));
           projectionList.add( Projections.alias(Projections.count("studentId"),"count"));
            criteria.setProjection(projectionList);
           criteria.addOrder(Order.desc(("count")));
            return criteria.list();

Answer 1

由于没有接受的答案-我格式化并简化了您自己的解决方案：

Criteria criteria = session.createCriteria(Student.class);
ProjectionList projectionList = Projections.projectionList();
projectionList.add(Projections.groupProperty("studentId"));
projectionList.add(Projections.count("studentId"), "count");
criteria.setProjection(projectionList);
criteria.addOrder(Order.desc(("count")));
return criteria.list();