系统密码长度为6 ~ 12个字符

Question

我是Python世界的新手，被赋予了完成以下任务的任务:

设计、编码、测试和评估一个系统，以接受和测试某些特征的密码:

• 至少6个字符，长度不超过12个字符。
• 系统必须提示密码失败及其原因，要求用户重新输入他们的选择，直到输入成功的密码。
• 必须显示可接受密码的消息。
• 密码强度可以根据简单的标准来评估其适用性;例如，只使用大小写字母和数字字符的密码系统可以评估密码强度如下:
  • WEAK如果只使用一种类型，例如全小写或全数字
  • MEDIUM如果使用两种类型
  • STRONG

到目前为止，我已经完成了以下操作，但没有使其正常工作:

def password():
    print ('Welcome user ! Please enter password belown')
    print ('The password entered must be between 6-12 characters longn')
    while True:
        password = input ('Please enter your password . . . :')
        weak = 'weak'
        med = 'medium'
        strong = 'strong'
        if len(password) >12:
            print ('password is too long It must be between 6 and 12 characters')
        elif len(password) <6:
            print ('password is too short It must be between 6 and 12 characters')
        elif len(password) >=6 and len(password) <= 12:
            print ('password okn')
            if password.lower()== password or password.upper()==password or password.isalnum()==password:
                print ('password is', weak)
            elif password.lower()== password and password.upper()==password or password.isalnum()==password and password.upper()==password:
                print ('password is', medium)
            else:
                password.lower()== password and password.upper()==password and password.isalnum()==password
                print ('password is', strong)
            break
password()

我尝试引入一个while循环:

while invalid:
    if len(password) >=6 and (password) <=12:
        password=False
        # number in range
        # sets invalid to False to stop loop
    else:
        print('Sorry the password you entered was not between 6 and 12 characters long')
        print('Please try again')
print('You have entered a valid password')

但仍然不能让它工作，请帮助!!

Answer 1

好吧，我不清楚你面临的具体问题是什么，但你检查密码强度中等的条件是草率的

 elif password.lower()== password and password.upper()==password or password.isalnum()==password and password.upper()==password:

建议考虑布尔变量

D ->至少包含1位数字的字符串

U -> string包含至少1个大写字母和

L->包含至少一个小写字符的字符串

D | U | L == low | medium | strong 
0   0   0     1
0   0   1     1 
0   1   0     1
0   1   1           1     
1   0   0     1
1   0   1           1
1   1   0           1
1   1   1                     1

只有一种方法可以认为密码是强的

可以通过使用regex

来计算D

_digits = re.compile('d')
def contains_digits(d):
    return bool(_digits.search(d))

条件U和L很容易计算

现在减少你的表达式

strong = D * U * L

medium = (!)D * U * L) + (D * !U * L) + (D * U * !L)

low = (!)D * ! u) + (!D * ! l) + (!U * !L)

所以你的代码看起来像

D = areDigits(Password)
U = areUpper(Password)
L = areLower(Password)

if((!D and !U) or (!D and !L) or (!U and !L)):
    print("weak password")
elif(D and U and L):
    print("strong password")
else:
    print("medium strength password")

这可能看起来有点难看，但这是一个更系统的方法来处理这个问题，想想如果你要包含特殊字符和其他要求，你会怎么做!

Answer 2

同意这是正则表达式的一个很好的用例。

也好像你的中大小写永远不会被触发:

elif password.lower()== password and password.upper()==password or password.isalnum()==password and password.upper()==password:
>>> 'a123'.lower() == 'a123' and 'a123'.upper() == 'a123'
False
>>> '1234'.isalnum() and '1234'.upper() == '1234'
True

因为lower和upper必须同时为真或者isalnum和isalupper必须同时被触发->但是A12345或12345被认为是弱的，所以它不能触发med…

你可以考虑为你的密码做一套测试服。

Answer 3

尝试根据各种条件检查您的密码，使用正则表达式搜索和匹配密码。你可能会发现这个链接很有用:

包含多个条件语句的密码检查器

Answer 4

你的代码有点难读。我会将密码的实际测试拆分为一个单独的函数，如下面的程序所示。

然后您可以更清楚地看到正在测试的内容，并且可以在主函数中对测试结果作出反应。

我使用一个密码类来存储测试结果，因为我喜欢它看起来很干净。

Python示例3:

import re
def check_password(chars, min_chars=6, max_chars=12):
    class Password: pass
    Password.has_uppercase = bool(re.search(r'[A-Z]', chars))
    Password.has_lowercase = bool(re.search(r'[a-z]', chars))
    Password.has_numbers = bool(re.search(r'[0-9]', chars))
    if not min_chars <= len(chars) <= max_chars:
        print("Password needs to be between %s and %s characters." % (min_chars, max_chars))
        return

     /* Return a list of only my attributes
        of the Password class. */
     return [t for t in vars(Password).items() if not t[0].startswith("__")]

if __name__ == "__main__":
    meanings = {0: "unacceptable", 1: "Weak", 2: "Medium", 3: "Strong"}
    while True:
        chars = input('nEnter a password: ')
        results = check_password(chars)
        if results:
            /* Points are equal to how many tests are successful */
            points = len([p[0] for p in results if p[1] is True])
            /* Print out the results to the console */
            print("nPassword strength is %s.n" % meanings.get(points))
            for condition, result in results:
                print("{0:<15} {1} {2}".format(condition, ":", bool(result)))
            break

Answer 5

while invalid:
    if len(password) >=6 and (password) <=12:
        password=False
        # number in range
        # sets invalid to False to stop loop
    else:
        print('Sorry the password you entered was not between 6 and 12 characters long')
        print('Please try again')
print('You have entered a valid password')