给定下表,
PersonID Year
---------- ----------
1 1991
1 1992
1 1993
1 1993
2 1990
2 1991
3 1991
3 1992
3 1994
有没有办法使用 SQL 选择查询来获取 PersonID,其中它至少有 3 行,连续年份在 1990 到 1995 年之间?在这种情况下,它应该只找到人员 ID 1。
感谢您的帮助。
我认为应该可以像下面这样的事情:
SELECT personID
FROM
(
SELECT
CASE WHEN year - min(year) OVER (PARTITION BY PersonID ORDER BY YEAR ASC ROWS BETWEEN 2 PRECEDING AND 2 PRECEDING) = 2 THEN 'x' END as ConsecutiveFlag,
PersonID
FROM
(SELECT personID, year FROM table GROUP BY personID,year) subquery
WHERE year BETWEEN 1990 and 1995
) t1
WHERE ConsecutiveFlag = 'x'
GROUP BY personID
它使用窗口函数按日期排序并查看两行。它将当前年份与前两行的值进行比较,如果差值为 2,则我们知道我们有连续的年份。
外部查询筛选标记的记录并返回人员 ID。
尝试:
select a.PersonID from Table a
left join Table b
on a.Personid = b.Personid and a.year = b.year + 1
left join Table c
on a.Personid = c.Personid and b.year = c.year + 1
where b.year is not null
and c.year is not null
and a.year <= 1995 and c.year >= 1990
您可以将表与自身连接起来:
declare @ConsecutiveYears as integer
set @ConsecutiveYears = 3
select distinct PersonYear.PersonID
from PersonYear
join PersonYear Consecutives
on PersonYear.PersonID = Consecutives.PersonID
and Consecutives.Year between PersonYear.Year and PersonYear.Year + @ConsecutiveYears - 1
where PersonYear.Year >= 1990 and Consecutives.Year <= 1995
Group by PersonYear.PersonID, PersonYear.Year
Having COUNT(distinct Consecutives.Year) = @ConsecutiveYears
您可以使用 2 个self joins
来完成此操作(您将在同一personId
上加入表格 3 次,并在每个连接中year
递增 1 以查找每个人的序列年份 3 次)
图式:
create table tbl_so(PersonID int,[Year] int)
insert into tbl_so values
(1, 1991),
(1, 1992),
(1, 1993),
(1, 1993),
(2, 1990),
(2, 1991),
(3, 1991),
(3, 1992),
(3, 1994)
查询:
select distinct t1.personId
from tbl_so t1
join tbl_so t2 on t1.[year]+1=t2.[year] and t1.personId=t2.personId
join tbl_so t3 on t2.[year]+1=t3.[year] and t2.personId=t3.personId
输出:
personId
1