我来自phpunit的assertEquals说我的字符串不相等，但我已经复制了它们，我认为这是由于在响应中添加了行

Question

我正在尝试使用 guzzle 运行一些测试来提示我的服务器输入 JSON 响应，我将将其与我预期的响应进行比较。问题是我无法获得与预期结果匹配的响应。我认为这主要是由于一些语法错误，但我不知道如何纠正这一点。

我已经尝试手动添加新行到输出应该是什么，但这只会将添加到字符串中。

请参阅下面的控制台报告：

1) UserAgentTest::testGet
Failed asserting that two strings are equal.
--- Expected
+++ Actual
@@ @@
-'{"error":false,"user":{"id_customer":10,"name":"Nic","email":"[e-mail]","password":"$2y$15$YN5A58syg5iIuHJ.5BR6j.ZpHGASqZID4l6k.M3xgH9jSPlojhzGK","x_coord":"-29.82188!-29.79044","y_coord":"31.02221!30.80688","address_name":"Home!Not home","address":"11 Rapson Road!11 everton road","country":null,"province":"KwaZulu-Natal!KwaZulu-Natal","city":"Durban!Durban","suburb":"Morningside!Kloof","postcode":"2639!3620","account":"sole","vat_num":"","reg_id":"","phone_number":"0836661065"}}'
+'
+
+{"error":false,"user":{"id_customer":10,"name":"Nic","email":"[e-mail]","password":"$2y$15$YN5A58syg5iIuHJ.5BR6j.ZpHGASqZID4l6k.M3xgH9jSPlojhzGK","x_coord":"-29.82188!-29.79044","y_coord":"31.02221!30.80688","address_name":"Home!Not home","address":"11 Rapson Road!11 everton road","country":null,"province":"KwaZulu-Natal!KwaZulu-Natal","city":"Durban!Durban","suburb":"Morningside!Kloof","postcode":"2639!3620","account":"sole","vat_num":"","reg_id":"","phone_number":"0836661065"}}'
C:wamp64wwwtestsUserAgentTest.php:32
FAILURES!
Tests: 2, Assertions: 3, Failures: 1.

Answer 1

"实际"字符串中有 2 个前导换行符：

+'
+
+{"error":false

您可以使用 PHP 的trim函数从字符串的开头和结尾去除空格。

self::assertEquals(trim($string1), trim($string2));

这将确保没有前导/尾随空格字符。

此外，您可能希望使用preg_replace剥离所有换行符：

self::assertEquals(
trim(preg_replace('/R+/', '', $string1)),
trim(preg_replace('/R+/', '', $string2))
);

Answer 2

您还可以使用二进制安全不区分大小写的字符串与strcasecmp

$this->assertEquals(0, strcasecmp($expected, $actual));