Ruby 将参数传递到内部方法中

Question

我是编程新手，我正在做rails。在这里，我有一个红宝石问题。

我有一个方法对应物，它将消息和对话作为参数

    def counterpart(message, conversation)
        if  message.author_id == conversation.sender_id
          counterpart_id = conversation.receiver_id
        else
          counterpart_id = conversation.sender_id
        end
    end

在下面的方法create_notification中，我想在 HANDLE 中调用对应方法以获取变量counterpart_id。但是，我如何将参数消息和对话传递给这里的对应方呢？

    def create_notification(message, conversation)
        counterpart(message, conversation)
        notification = message.create_notification(
                  notifier_id: message.author_id,
                  receiver_id: counterpart_id,
                  content: "#{message.author.name} sent you a message",
                  title: "message")
    end

谢谢

Answer 1

我们对您的模型了解不够。所以，据我所知，让你的代码工作的最佳方法是移动到

def counterpart(message, conversation)
  message.author_id == conversation.sender_id ? conversation.receiver_id : conversation.sender_id
end
def create_notification(message, conversation)
  message.create_notification(notifier_id: message.author_id,
      receiver_id: counterpart(message, conversation),
      content: "#{message.author.name} sent you a message",
      title: "message")
end