每30秒钟呼叫方法不起作用

Question

我想在每30秒内更新用户位置，而我使用的是射击请求。Bellow中的代码：

public class CarLocationUpdateService extends Service {

    Context context;
    long delay = 1000; // delay for 1 sec.
    long period = 10000; // repeat every 10 sec.
    @Nullable
    @Override
    public IBinder onBind(Intent intent) {
        return null;
    }
    @Override
    public int onStartCommand(Intent intent, int flags, int startId) {
        context = this;

        Handler ha=new Handler();
        ha.postDelayed(new Runnable() {
            @Override
            public void run() {
                //call function
                CarLocationUpdateVolleyClass carLocationUpdateVolleyClass=new CarLocationUpdateVolleyClass(context);
                carLocationUpdateVolleyClass.carLocationRequest();
            }
        }, delay);

        return START_STICKY;
    }
    @Override
    public void onDestroy() {
        super.onDestroy();
    }
}

Answer 1

使用firbasejobdispatcher使用JobsChedulerhttps://developer.android.com/topic/performance/scheduling.html

Answer 2

您可以使用融合的位置服务获取位置更新。我创建了一个服务以获取位置更新。此代码将为您提供onLocationChanged方法中的位置。在这里查看我的答案

Answer 3

尝试以下：

mHandler = new Handler();
    Runnable r = new Runnable() {
        @override 
        public void run() {
            f();
            mHandler.postDelayed(this, 30000);
        }
    };
    mHandler.postDelayed(r, 30000);

Answer 4

您必须在可运行的内部再次调用handler.postDelayed()方法，因为它仅执行一次，这是正常的行为。像这样将可运行的人分开：

Handler ha = new Handler();
private Runnable yourRunnable = new Runnable() {
    @Override
    public void run() {
  CarLocationUpdateVolleyClass carLocationUpdateVolleyClass=new CarLocationUpdateVolleyClass(context);
                carLocationUpdateVolleyClass.carLocationRequest();
     ha.postDelayed(yourRunnable, 30000);
    }
};
ha.post(yourRunnable);

顺便说一句，您的问题告诉我们一些大约30秒的东西，但您只每10秒钟称呼它。

Answer 5

尝试一下，它起作用

public void doWork(){
        new Handler().postDelayed(new Runnable() {
            @Override
            public void run() {
                // This method will be executed once the timer is over
                // insert your data to db here

                // close this activity
               doWork();
                Toast.makeText(MainActivity.this, "LOL", Toast.LENGTH_SHORT).show();
            }
        }, TIME_OUT);
    }

然后简单地调用onStartCommand()

中的此方法

doWork();

Answer 6

   final Handler ha=new Handler();
    Runnable runnable = new Runnable() {
        @Override
        public void run() {
            // ...
            ha.postDelayed(this,30000);
        }
    };
    ha.post(runnable);