将基于类的视图转换为'normal'视图

Question

我已经编写了以下django-rest框架视图：

# urls.py
url(r'user/company', views.UserViewSet.as_view({"get": "companyInfo"}), name="company_info"),
# views.py
class UserViewSet(viewsets.ModelViewSet):
serializer_class = UserSerializer
queryset = User.objects.all()
permission_classes = (permissions.IsAuthenticated,)
@action(methods=["get"], detail=True)
def companyInfo(self, request):
user = request.user
company = user.get_company()
detail = {}
detail['company'] = company.name
detail['num_users'] = company.num_licenses if company else None        
return Response(detail) 

我该如何使用django-rest框架编写与"正常"django视图完全相同的视图呢。例如，类似这样的东西：

# urls.py
path('user/company/', views.company_info, name='company_info'),
# views.py
@require_GET
def company_info(request):
user = request.user
company = user.get_company()
detail = {}
detail['company'] = company.name
detail['num_users'] = company.num_licenses if company else None        
return Response(detail) 

我想以上只是一个开始，但我认为我仍然需要正确地进行身份验证(使用jwt(，UserViewSet会自动使用permission_classes = (permissions.IsAuthenticated,)进行身份验证。

Answer 1

您非常接近。您需要添加两个decorator，使其成为一个经过验证的API视图，就像ClassView:中一样

# path('user/company/', views.company_info, name='company_info'),
@api_view(['GET'])
@permission_classes((permissions.IsAuthenticated,))
def company_info(request):
user = request.user
company = user.get_company()
detail = {}
detail['company'] = company.name
detail['num_users'] = company.num_licenses if company else None
detail['company_admin'] = company.admin_user.name if company else None
return Response(detail)