java.lang.ArrayIndexOutOfBoundsException in sqlite (android)

Question

我在sqlite中创建了一个表，给了我java.lang.ArrayIndexOutOfBoundsException这是代码：

db.execSQL("CREATE TABLE "+scoreboardTable+" ("+scoreboard_id+ " INTEGER PRIMARY KEY NOT NULL,"+" FOREIGN KEY ( "+player_fk+ ") REFERENCES "+playerTable+" ("+playerid+ "), "
        +"FOREIGN KEY ( "+ Template_fk+ ") REFERENCES " +TemplateTable+" ("+ templateid+ "),"+ total_flick+"int"+surprise_success+"varchar"+surprise_failure+"varchar)");
    }

和

public void Insert_scoreboard(String[] str) 
    {
        try
        {
        SQLiteDatabase DB= this.getWritableDatabase();
        ContentValues cv=new ContentValues();
        cv.put("scoreboard_id", str[0]);
        cv.put("player_fk", str[1]);
        cv.put("Template_fk", str[2]);
        cv.put("total_flick", str[3]);
        cv.put("surprise_success", str[4]);
        cv.put("surprise_failure", str[5]);

        DB.insert( scoreboardTable , "scoreboard", cv);
        DB.close();
        }
        catch(Exception ex)
        {
            ex.toString();
        }

我做错了.

Answer 1

您在Create Table Syntax中出错（您忘记了逗号，在某些地方）使用以下代码更新您的代码，

db.execSQL( "CREATE TABLE " + scoreboardTable + " (" + scoreboard_id + " INTEGER PRIMARY KEY NOT NULL," + " FOREIGN KEY ( "+player_fk+ ") REFERENCES " + playerTable + " (" + playerid + "), " + "FOREIGN KEY ( " + Template_fk + ") REFERENCES " + TemplateTable + " (" + templateid + ")," + total_flick + "int, " + surprise_success + "varchar, " + surprise_failure + "varchar)" );
    }