两个矩形逻辑错误

Question

该程序假定采用（x，y）坐标以及两个矩形的宽度和高度，并用字符串显示两个矩形，说明它们重叠，包含或不重叠。我有正确的图形。但我的问题在于要显示的字符串的逻辑。当用户为不包含或相互重叠的三角形输入数据时。它说它们重叠。我需要帮助修复代码的逻辑。

import javafx.application.Application;
import javafx.scene.Scene;
import javafx.scene.layout.Pane;
import javafx.scene.paint.Color;
import javafx.scene.shape.Rectangle;
import javafx.scene.text.Text;
import javafx.stage.Stage;
import java.util.ArrayList;
import java.util.Scanner;
public class TwoRectangles extends Application {
    public void start(Stage primaryStage) throws Exception {
        Pane pane = new Pane();
        double width = 400;
        double height = 400;
        ArrayList<Rectangle> rectangles = new ArrayList<>();
        Scanner input = new Scanner(System.in);
        for (int i = 1; i <= 2; i++) {
            System.out.print("Enter (x, y) of center, width, and height or rec " + i + ": ");
            Rectangle temp = new Rectangle(input.nextDouble(), input.nextDouble(), input.nextDouble(),
                input.nextDouble());
            temp.setFill(Color.TRANSPARENT);
            temp.setStroke(Color.BLACK);
            rectangles.add(temp);
        }
        Rectangle rec1 = rectangles.get(0);
        Rectangle rec2 = rectangles.get(1);
        String s = "";
        if (!(rec1.contains(rec2.getWidth(), rec2.getHeight()) 
            || rec2.contains(rec1.getWidth(), rec1.getHeight()))) {
            s = "One rectangle is contained in another.";
        } else if (rec1.intersects(rec2.getX(), rec2.getY(), rec2.getWidth(), rec2.getHeight())
            || rec2.intersects(rec1.getX(), rec1.getY(), rec1.getWidth(), rec1.getHeight())) {
            s = "One rectangle overlaps another." ;
        } else {
            s = "The rectangles do not overlap.";
        }
        Text text = new Text(width * 0.1, height * 0.9, s);
        pane.getChildren().add(text);
        pane.getChildren().addAll(rectangles);
        primaryStage.setTitle("rectangles..");
        primaryStage.setScene(new Scene(pane, width, height));
        primaryStage.show();
    }
    public static void main(String[] args) {
        launch(args);
    }
}

Answer 1

看起来您的主要问题是您的"包含"检查。 它只考虑矩形的宽度和高度，而不考虑它们的位置。 你可以写一个"包含"方法，比如：

private static boolean contains(Rectangle r1, Rectangle r2) {
    return r1.getX() <= r2.getX() && r1.getY() <= r2.getY()
            && r2.getX() + r2.getWidth() <= r1.getX() + r1.getWidth()
            && r2.getY() + r2.getHeight() <= r1.getY() + r1.getHeight();
}

然后将支票更改为

    if (contains(rec1, rec2) || contains(rec2, rec1)) {
        s = "One rectangle is contained in another.";
    } else if (rec1.intersects(rec2.getX(), rec2.getY(), rec2.getWidth(), rec2.getHeight())) {
        s = "One rectangle overlaps another.";
    } else {
        s = "The rectangles do not overlap.";
    }

（你只需要单向检查交集，因为如果矩形 A 与 B 相交，那么 B 也与 A 相交）。

Answer 2

嗯，"包含"很简单：

boolean contain = rect1.contains(rect2) || rect2.contains(rect1);

之后，"重叠"很容易：

boolean overlap = ! contain && rect1.intersects(rect2);

或者，要获取字符串，请执行以下操作：

String s = (rect1.contains(rect2) || rect2.contains(rect1)
            ? "One rectangle is contained in another."
            : rect1.intersects(rect2)
              ? "One rectangle overlaps another."
              : "The rectangles do not overlap.");