我正在尝试用Java(适用于Android)制作Wake-On-Lan应用程序,所以我搜索了一下,发现了以下代码:
import java.io.*;
import java.net.*;
public class WakeOnLan {
public static final int PORT = 9;
public static void main(String[] args) {
if (args.length != 2) {
System.out.println("Usage: java WakeOnLan <broadcast-ip> <mac-address>");
System.out.println("Example: java WakeOnLan 192.168.0.255 00:0D:61:08:22:4A");
System.out.println("Example: java WakeOnLan 192.168.0.255 00-0D-61-08-22-4A");
System.exit(1);
}
String ipStr = args[0];
String macStr = args[1];
try {
byte[] macBytes = getMacBytes(macStr);
byte[] bytes = new byte[6 + 16 * macBytes.length];
for (int i = 0; i < 6; i++) {
bytes[i] = (byte) 0xff;
}
for (int i = 6; i < bytes.length; i += macBytes.length) {
System.arraycopy(macBytes, 0, bytes, i, macBytes.length);
}
InetAddress address = InetAddress.getByName(ipStr);
DatagramPacket packet = new DatagramPacket(bytes, bytes.length, address, PORT);
DatagramSocket socket = new DatagramSocket();
socket.send(packet);
socket.close();
System.out.println("Wake-on-LAN packet sent.");
}
catch (Exception e) {
System.out.println("Failed to send Wake-on-LAN packet: + e");
System.exit(1);
}
}
private static byte[] getMacBytes(String macStr) throws IllegalArgumentException {
byte[] bytes = new byte[6];
String[] hex = macStr.split("(\:|\-)");
if (hex.length != 6) {
throw new IllegalArgumentException("Invalid MAC address.");
}
try {
for (int i = 0; i < 6; i++) {
bytes[i] = (byte) Integer.parseInt(hex[i], 16);
}
}
catch (NumberFormatException e) {
throw new IllegalArgumentException("Invalid hex digit in MAC address.");
}
return bytes;
}
}
我在我的电脑上试过了,它起作用了,但对安卓系统不起作用:(我试过编辑它,但仍然一无所获:)这是我的安卓代码:
import java.net.DatagramPacket;
import java.net.DatagramSocket;
import java.net.InetAddress;
import com.macura.wakemypc.MainActivity;
import com.macura.wakemypc.R;
import com.macura.wakemypc.MainActivity;
import com.macura.wakemypc.MainActivity;
import android.os.Bundle;
import android.app.Activity;
import android.view.Menu;
import android.view.View;
import android.widget.EditText;
public class MainActivity extends Activity {
public static final int PORT = 9;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
// Inflate the menu; this adds items to the action bar if it is present.
getMenuInflater().inflate(R.menu.main, menu);
return true;
}
public void buttonClick(View view) {
EditText iptext = (EditText)findViewById(R.id.editText1);
EditText mactext = (EditText)findViewById(R.id.editText2);
String mac = mactext.toString();
String broadcastIP = iptext.toString();
MainActivity.wakeup(broadcastIP, mac);
}
private static byte[] getMacBytes(String mac) throws IllegalArgumentException {
// TODO Auto-generated method stub
byte[] bytes = new byte[6];
if (mac.length() != 12)
{
throw new IllegalArgumentException("Invalid MAC address...");
}
try {
String hex;
for (int i = 0; i < 6; i++) {
hex = mac.substring(i*2, i*2+2);
bytes[i] = (byte) Integer.parseInt(hex, 16);
}
}
catch (NumberFormatException e) {
throw new IllegalArgumentException("Invalid hex digit...");
}
return bytes;
}
public static void wakeup(String broadcastIP, String mac) {
if (mac == null) {
return;
}
try {
byte[] macBytes = getMacBytes(mac);
byte[] bytes = new byte[6 + 16 * macBytes.length];
for (int i = 0; i < 6; i++) {
bytes[i] = (byte) 0xff;
}
for (int i = 6; i < bytes.length; i += macBytes.length) {
System.arraycopy(macBytes, 0, bytes, i, macBytes.length);
}
InetAddress address = InetAddress.getByName(broadcastIP);
DatagramPacket packet = new DatagramPacket(bytes, bytes.length, address, 5555);
DatagramSocket socket = new DatagramSocket();
socket.send(packet);
socket.close();
}
catch (Exception e) {
}
}
}
每次我输入ip和mac地址时,它都不会起任何作用。那么,你能帮我吗?:)是的,很抱歉我的英语:D
我不在乎其余的代码,但您应该使用String mac = mactext.getText().toString();
而不是String mac = mactext.toString();
,因为如果不进行此更改,您将转换为字符串整个EditText,而不仅仅是其值。附言:我知道这是10个月后的问题,但对于任何来这里寻找WOL android代码的人来说,它应该是有用的
我知道现在有点晚了,但我也花了很长时间让这段java代码在android上运行。解决方案是使用广播ip。仅此而已。干杯j