目标C如何填充NSArray的rangeOfString

Question

我想知道是否有可能填充一个NSArray的rangeOfString对象。因为在rangeOfString:之后我有一个很长的对象列表NSArray biglist ' s count大于list ' s count。

我想从主列表的小列表中过滤掉对象。

如果不清楚，请告诉我。

我的代码如下:

NSArray *biglist = [[NSArray alloc] initWithArray:
                        [[NSString stringWithContentsOfFile:[[NSBundle mainBundle] pathForResource:@"mainlist" ofType:@"txt"]
                                                   encoding:NSUTF8StringEncoding error:NULL] componentsSeparatedByString:@"n"]];

NSArray *list = [[NSArray alloc] initWithArray:
                        [[NSString stringWithContentsOfFile:[[NSBundle mainBundle] pathForResource:@"smalllist" ofType:@"txt"]
                                                   encoding:NSUTF8StringEncoding error:NULL] componentsSeparatedByString:@"n"]];
    for (NSString *listword in list);
    NSMutableArray *wordlist = [[NSMutableArray alloc] init];
    NSMutableArray *worindex = [[NSMutableArray alloc] init];
    NSMutableIndexSet *mindexes = [[NSMutableIndexSet alloc] init];
    NSMutableDictionary *mutdic = [[NSMutableDictionary alloc] init]; 
    NSMutableArray *mutarray = [[NSMutableArray alloc] init];
    for (NSString *s in mainlist)
    {
        NSRange ran = [s rangeOfString:listword];
        if (ran.location !=NSNotFound)
                {
                //my codes here
                }
        }

---

编辑:

我想我可以通过写

来解决这个问题

int i;
for (i = 0; i<[list count]; i++)
{
    NSString *same = [list objectAtIndex:i];
    NSLog (@"listword: %@", same);
}

但是我不确定把它放在哪里，在mainlist的for循环中还是在外面。

---

编辑:这个for循环在主for循环中工作。

---

编辑:我试过这些代码，但不知怎么的它不工作。

NSArray *list = [[NSArray alloc] initWithArray:
                     [[NSString stringWithContentsOfFile:[[NSBundle mainBundle] pathForResource:@"small" ofType:@"txt"]
                                                encoding:NSUTF8StringEncoding error:NULL] componentsSeparatedByString:@"n"]];

    NSArray *mainlist = [[NSArray alloc] initWithArray:
                        [[NSString stringWithContentsOfFile:[[NSBundle mainBundle] pathForResource:@"mainlist" ofType:@"txt"]
                                                   encoding:NSUTF8StringEncoding error:NULL] componentsSeparatedByString:@"n"]];
    NSMutableArray *large = [NSMutableArray arrayWithArray:mainlist];

    NSArray *newlarge;
    for (NSString *listword in list)
    {
    NSPredicate *predicate = [NSPredicate predicateWithFormat:@"(SELF beginswith[c] %@)",listword];
    newlarge = [large filteredArrayUsingPredicate:predicate];
    }
    NSLog (@"large: %@", newlarge);
    NSLog (@"finished!");

Answer 1

"我想从主列表的小列表中过滤掉对象。"

如果我理解正确的话，您想要从另一个数组中删除一个数组的项。你不希望在n^2循环中做那么多的工作和分配。

从另一个数组中移除一个数组的项。这取决于你的数组有多大，你可能需要进一步优化，但这是有效的:

NSArray *small = [NSArray arrayWithObjects:@"three", @"two", nil];
NSMutableArray *large = [NSMutableArray arrayWithObjects:@"one", @"two", @"three", @"four", nil];
[large removeObjectsInArray:small];
// print
for (NSString *current in large)
{
    NSLog(@"item: %@", current);
}

这个输出:

2011-10-13 08:39:21.176 Craplet[5235:707] item: one
2011-10-13 08:39:21.178 Craplet[5235:707] item: four

Answer 2

我自己想出来并解决了这个问题:)它几乎可以完美地工作。

我的代码:

NSArray *big = [[NSArray alloc] initWithObjects:@"hello ->mache", @"heisann hoppsann ->hiya", @"nei men ->da", @"however ->what", @"may ->april", @"mai ->maj", nil];
NSArray *small = [[NSArray alloc] initWithObjects: @"heisann ", @"nei men ", @"however ", @"mai", nil];
NSMutableArray *smallwithh = [[NSMutableArray alloc] init];
NSMutableIndexSet *mindexes = [[NSMutableIndexSet alloc] init];
for (NSString *same in small)
{
    NSLog (@"listword: %@", same);
    for (NSString *s in big)
    {
        NSRange ran = [s rangeOfString:same];
        if (ran.location !=NSNotFound)
        {
            [smallwithh addObject:s];
            NSUInteger ind = [big indexOfObject:s];
            [mindexes addIndex:ind];
        }
    }
}
NSLog (@"smallwith: %@", smallwithh);
[smallwithh release];
NSMutableArray *newWords =[NSMutableArray arrayWithArray: big];
[newWords removeObjectsAtIndexes: mindexes];
[big release];      
[small release];
NSLog (@"newWords: %@", newWords);