向PFquery添加唯一对象,即user



我试图将关注用户的列表添加到用户下标题为"追随者"的列,这是从发件人标记的objectatindex中检索的。下面是代码:

-(void)followButton:(id)sender {

UIButton *senderButton = (UIButton *)sender;
NSLog(@"current Row=%ld",(long)senderButton.tag);
PFObject *object = [self.objects objectAtIndex:senderButton.tag];
if (![[object objectForKey:@"followers"]containsObject:[PFUser currentUser].objectId]) {
    [[PFUser currentUser] addUniqueObject:object.objectId forKey:@"following"];
    [[PFUser currentUser] saveInBackground];

    PFUser *otherUser = [self.objects objectAtIndex:senderButton.tag];
    NSLog(@"Followed %@", otherUser);
    [otherUser addUniqueObject:[PFUser currentUser].objectId forKey:@"followers"];
    [otherUser saveInBackground];

  // NSLog(@"Followed %@", object);

} else {
    [[PFUser currentUser] removeObject:object.objectId forKey:@"following"];
    [[PFUser currentUser] saveInBackground];
    PFUser *otherUser = [self.objects objectAtIndex:senderButton.tag];
    [otherUser removeObject:[PFUser currentUser].objectId forKey:@"followers"];
    [otherUser saveInBackground];

        }
[self.tableView reloadData];
}

由于某种原因,上面的代码只添加到当前用户的"Following"数组中。当重新单击时,对象将被删除,但什么也没有发生。另外,代码

 PFUser *otherUser = [self.objects objectAtIndex:senderButton.tag];
    [otherUser removeObject:[PFUser currentUser].objectId forKey:@"followers"];
    [otherUser saveInBackground];

绝对不做任何事情,同时它应该做的工作是在选定行添加用户的"追随者"数组。我做错了什么?目标是得到一个工作的追随者/追随者的行动。我正在使用PFQueryTableViewController!

您不能从客户端修改其他用户的对象。只能修改当前用户。修改当前用户的方法是使用Parse.Cloud.useMasterKey();

在云代码中使用主密钥。https://parse.com/questions/how-can-i-allow-a-user-to-edit-another-user

因此,通过传递"otherUser"的用户名和要删除的objectId,在云代码中创建一个函数

Parse.Cloud.define("RemoveFollower", function(request, response){
var username = request.params.username;
var id_to_remove = request.params.objectId_passed;
var query = new Parse.Query(Parse.User);
query.equalTo("username", username);
query.find({
    success: function(results){
        var u = results[0];
        //u modify the user u however you like...
        u.save();
        response.success("Success");
    },
    error: function(){
        response.error("Error");
    }
    });

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