我试图将关注用户的列表添加到用户下标题为"追随者"的列,这是从发件人标记的objectatindex中检索的。下面是代码:
-(void)followButton:(id)sender {
UIButton *senderButton = (UIButton *)sender;
NSLog(@"current Row=%ld",(long)senderButton.tag);
PFObject *object = [self.objects objectAtIndex:senderButton.tag];
if (![[object objectForKey:@"followers"]containsObject:[PFUser currentUser].objectId]) {
[[PFUser currentUser] addUniqueObject:object.objectId forKey:@"following"];
[[PFUser currentUser] saveInBackground];
PFUser *otherUser = [self.objects objectAtIndex:senderButton.tag];
NSLog(@"Followed %@", otherUser);
[otherUser addUniqueObject:[PFUser currentUser].objectId forKey:@"followers"];
[otherUser saveInBackground];
// NSLog(@"Followed %@", object);
} else {
[[PFUser currentUser] removeObject:object.objectId forKey:@"following"];
[[PFUser currentUser] saveInBackground];
PFUser *otherUser = [self.objects objectAtIndex:senderButton.tag];
[otherUser removeObject:[PFUser currentUser].objectId forKey:@"followers"];
[otherUser saveInBackground];
}
[self.tableView reloadData];
}
由于某种原因,上面的代码只添加到当前用户的"Following"数组中。当重新单击时,对象将被删除,但什么也没有发生。另外,代码
PFUser *otherUser = [self.objects objectAtIndex:senderButton.tag];
[otherUser removeObject:[PFUser currentUser].objectId forKey:@"followers"];
[otherUser saveInBackground];
绝对不做任何事情,同时它应该做的工作是在选定行添加用户的"追随者"数组。我做错了什么?目标是得到一个工作的追随者/追随者的行动。我正在使用PFQueryTableViewController!
您不能从客户端修改其他用户的对象。只能修改当前用户。修改当前用户的方法是使用Parse.Cloud.useMasterKey();
在云代码中使用主密钥。https://parse.com/questions/how-can-i-allow-a-user-to-edit-another-user因此,通过传递"otherUser"的用户名和要删除的objectId,在云代码中创建一个函数
Parse.Cloud.define("RemoveFollower", function(request, response){
var username = request.params.username;
var id_to_remove = request.params.objectId_passed;
var query = new Parse.Query(Parse.User);
query.equalTo("username", username);
query.find({
success: function(results){
var u = results[0];
//u modify the user u however you like...
u.save();
response.success("Success");
},
error: function(){
response.error("Error");
}
});