如何在用户输入"y"的情况下重新启动我的游戏？为赛后创建了一个用户定义的函数

Question

i=1

玩另一个或退出游戏

def done():
quitvalue=str(input("Play Again?(y/n):"))
if quitvalue=='n' and i==0:
SystemExit
elif quitvalue=="y":
i=1

#Loop to Restart Game
def rps(play1,play2):
#Check Winner of Game
if play1==play2:
print("It's a tie!")
done()
elif play1=='r':
if play2=='s':
print(play1name+" Wins!")
done()
else:
print(play2name+" Wins!")
done()

elif play1=='p':
if play2=='r':
print(play1name+" Wins!")
done()
else:
print(play2name+" Wins!")
done()
elif play1=='s':
if play2=='p':
print(play1name+" Wins!")
done()
else:
print(play2name+" Wins!")
done()

#Player Input
while i==1:
play1name=str(input("Player 1 Name?:"))
play2name=str(input("Player 2 Name?:"))
play1= str(input(play1name+" Choose Rock(r),Paper(p), Scissors(s):"))
play2= str(input(play2name+" Choose Rock(r),Paper(p), Scissors(s):"))
i=0
rps(play1,play2)

Answer 1

这里的问题是done()函数中的i是指由 deafult 在函数中本地声明的变量i，而不是在程序开始时声明的全局变量i。 若要解决此问题，请在引用i之前在done()函数中添加global i：

def done():
global i
quitvalue=str(input("Play Again?(y/n):"))
if quitvalue=='n' and i==0:
SystemExit
elif quitvalue=="y":
i=1

Answer 2

你的意思是在你的done()函数中raise SystemExit退出吗？

如果是这样，则无需跟踪名称不明确的变量i并处理范围问题。有关一些有用的解释，请参阅此处。

您还应该将玩家名称输入移出游戏循环，input()将返回一个字符串。

我已经整理了代码并删除了一些不必要的重复部分。

def done():
"""Prompt user to continue or exit"""
quit_value = input("Play Again?(y/n): ").lower()
if quit_value == 'n':
raise SystemExit
def rps(play1, play2):
"""Play a single round of Rock, Paper, Scissors"""
# Check Winner of Game
if play1 == play2:
print("It's a tie!")
elif play1 == 'r':
if play2 == 's':
print(play1name + " Wins!")
else:
print(play2name + " Wins!")
elif play1 == 'p':
if play2 == 'r':
print(play1name + " Wins!")
else:
print(play2name + " Wins!")
elif play1 == 's':
if play2 == 'p':
print(play1name + " Wins!")
else:
print(play2name + " Wins!")
# get player names
play1name = input("Player 1 Name?: ")
play2name = input("Player 2 Name?: ")
# Player Input
while True:  # done() exits the program, so loop forever
play1 = input(play1name + " Choose Rock(r),Paper(p), Scissors(s): ")
play2 = input(play2name + " Choose Rock(r),Paper(p), Scissors(s): ")
# resolve the plays
rps(play1, play2)
# check for a rematch
done()

您可能还需要在rps()函数中检查有效的移动。