滤清器管路短路

Question

我有一个管道，用于过滤客户端的日期。现在看起来像：

import { Pipe, PipeTransform } from '@angular/core';
@Pipe({
name: 'filter'
})
export class FilterPipe implements PipeTransform {
transform(clients: any[], searchText: string): any[] {
if(!clients) return [];
if(!searchText) return clients;
searchText = searchText.toLowerCase();
return clients.filter( it => {
if (it.firstName.toLowerCase().includes(searchText)) {
return it.firstName.toLowerCase().includes(searchText);
}
if (it.lastName.toLowerCase().includes(searchText)) {
return it.lastName.toLowerCase().includes(searchText);
}
if (it.street.toLowerCase().includes(searchText)) {
return it.street.toLowerCase().includes(searchText);
}
if (it.city.toLowerCase().includes(searchText)) {
return it.city.toLowerCase().includes(searchText);
}
if (it.zipCode.toLowerCase().includes(searchText)) {
return it.zipCode.toLowerCase().includes(searchText);
}
if (it.country.toLowerCase().includes(searchText)) {
return it.country.toLowerCase().includes(searchText);
}
if (it.email.toLowerCase().includes(searchText)) {
return it.email.toLowerCase().includes(searchText);
}
if (it.phone.toLowerCase().includes(searchText)) {
return it.phone.toLowerCase().includes(searchText);
}
});
}
}

但我理解，条件可以写得更短。请告诉我，我该怎么做？。。

Answer 1

您可以使用这种方式

return clients.filter(function (item: any) {
for (let property in item) {
if (item[property] === null) {
continue;
}
if (item[property].toString().toLowerCase().includes(searchText)) {
return true;
}
}
return false;
});

Answer 2

这里有一个写条件的较短方法：

return clients.filter(it => 
it.firstName.toLowerCase().includes(searchText) ||
it.lastName.toLowerCase().includes(searchText) ||
it.street.toLowerCase().includes(searchText) ||
it.city.toLowerCase().includes(searchText) ||
it.zipCode.toLowerCase().includes(searchText) ||
it.country.toLowerCase().includes(searchText) ||
it.email.toLowerCase().includes(searchText) ||
it.phone.toLowerCase().includes(searchText)
);