Graphql使用Apollo重构查询，返回对象是重复的(diff查询中的相同字段)

Question

我有几个查询具有相同的返回类型：

// Query 1
gql`
mutation insert_shops_users($shopId: uuid) {
insert_shops_users(objects: [{ shopId: $shopId }]) {
affected_rows
returning {
Shop {
id
users {
userId
}
}
}
}
}
`,

// Query 2
gql`
mutation delete_shops_users_by_pk($shopId: uuid!, $userId: String!) {
delete_shops_users_by_pk(shopId: $shopId, userId: $userId) {
Shop {
id
users {
userId
}
}
}
}
`,

现在，我想提取这个部分，例如名称为ShopUserResult的部分，并在两个查询中使用它：

在ShopUserResult下提取

Shop {
id
users {
userId
}
}

结果查询

// Query 1 - after refactor
gql`
mutation insert_shops_users($shopId: uuid) {
insert_shops_users(objects: [{ shopId: $shopId }]) {
affected_rows
returning {
ShopUserResult
}
}
}
`,

// Query 2 - after refactor
gql`
mutation delete_shops_users_by_pk($shopId: uuid!, $userId: String!) {
delete_shops_users_by_pk(shopId: $shopId, userId: $userId) {
ShopUserResult
}
}
`,

我是graphql的新手，任何关于重构的建议都将不胜感激，谢谢。

Answer 1

可以使用片段(源1，源2(重构重复的字段集：

查询-之前

gql`
mutation insert_shops_users($shopId: uuid) {
insert_shops_users(objects: [{ shopId: $shopId }]) {
affected_rows
returning {
Shop {
id
users {
userId
}
}
}
}
}
`,

查询-使用片段后

碎片

const ShopWithUsers = gql`
fragment ShopWithUsers on shops {
id
users {
userId
}
}
`

查询

gql: gql`
mutation insert_shops_users($shopId: uuid) {
insert_shops_users(objects: [{ shopId: $shopId }]) {
affected_rows
returning {
Shop {
...ShopWithUsers
}
}
}
}
${ShopWithUsers}
`,