我发现一个脚本检查索引在谷歌如果网站有索引
function getPagesIndexedGoogle($site)
{
if ($site) {
$curl = curl_init();
curl_setopt_array($curl, array(
CURLOPT_HEADER => 0,
CURLOPT_RETURNTRANSFER => 1,
CURLOPT_URL => "https://www.google.com.au/search?q=site:$site&gws_rd=ssl",
CURLOPT_SSL_VERIFYPEER=> false,
CURLOPT_USERAGENT => 'Mozilla/5.0 (Windows NT 6.3; Trident/7.0; rv:11.0) like Gecko'
));
$result_string = curl_exec($curl);
curl_close($curl);
if (strpos($result_string, "did not match any documents") !== false) {
return 0;
} else {
$match = preg_match("/about ([0-9,]{0,12})/i", $result_string, $matches);
echo $matches[1];
}
}
}
if($_POST['domain']){
$site = $_POST['domain'];
}
echo $_POST['domain'] ;
echo getPagesIndexedGoogle($site);
?>
如何检查多个url?
我已经使用Foreach,但它不工作。
按照要求,这应该能成功:
<?php
function getPagesIndexedGoogle($site)
{
if ($site) {
$curl = curl_init();
curl_setopt_array($curl, array(
CURLOPT_HEADER => 0,
CURLOPT_RETURNTRANSFER => 1,
CURLOPT_URL => "https://www.google.com.au/search?q=site:$site&gws_rd=ssl",
CURLOPT_SSL_VERIFYPEER=> false,
CURLOPT_USERAGENT => 'Mozilla/5.0 (Windows NT 6.3; Trident/7.0; rv:11.0) like Gecko'
));
$result_string = curl_exec($curl);
curl_close($curl);
if (strpos($result_string, "did not match any documents") !== false) {
return 0;
} else {
$match = preg_match("/about ([0-9,]{0,12})/i", $result_string, $matches);
echo $matches[1];
}
}
}
if(!empty($_POST['domain'])){
// Tries to split URLs by new line or space character
$sites = preg_split('#\r\n|\r|\n| #i', $_POST['domain']);
foreach($sites as $site){
// Checks if the URL is a valid website or not (http(s):// must be included!)
if(preg_match('#((https?|ftp)://(S*?.S*?))([s)[]{},;"':<]|.s|$)#i', $site)){
echo $site;
echo getPagesIndexedGoogle($site);
} else {
echo $site;
echo " is not a valid url.";
}
}
} else {
echo "No websites were entered.";
}
?>
我仍然建议你不要使用文本区,而是使用简单的文本字段。它只是不容易出错。