我需要让我的号码以二进制打印出来。此数字是计算的总和。我的代码不起作用

Question

.data 
prompt:.asciiz "nEnter an integer: " 
add: .asciiz "n The sum in decimal is: "
bin: .asciiz "n The sum in binary is: "
sgt: .asciiz "n The second integer is greater than the first. "
fgt: .asciiz "n The first integer is greater than the second."
equal: .asciiz "n The two entered values are equal: "
.text
main:
li $v0, 4 #print string code
la $a0, prompt #argument
syscall #execute, service print stri
li $v0, 5 # read integer
syscall #v0 gets the returned value
move $s0, $v0 #set v0 -> s0
li $v0, 4 
la $a0, prompt
syscall
li $v0, 5
syscall
move $s1, $v0 #set v0 -> s1
add  $s2, $s1, $s0 #s2 -> s0 + s1
li $v0, 4 #print string
la $a0, add #argument
syscall 
move $a0, $s2
li $v0, 1 #print int
syscall
# Output "sum in binary is:".  
la $a0, bin
li $v0, 4
syscall

# Output the binary number.  (This is done by isolating one bit
# at a time, adding it to the ASCII code for '0', and outputting
# the character.  It is important that the bits are output in
# most-to-least significant bit order.
move $t2, $a0
li $s1, 32         # Set up a loop counter
Loop:
    rol $t2, $t2, 1    # Roll the bits left by one bit - wraps highest bit to lowest bit.
    and $t0, $t2, 1    # Mask off low bit (logical AND with 000...0001)
    add $t0, $t0, 48   # Combine it with ASCII code for '0', becomes 0 or 1 
    move $a0, $t0      # Output the ASCII character
    li $v0, 11
    syscall
    subi $s1, $s1, 1   # Decrement loop counter
    bne $s1, $zero, Loop  # Keep looping if loop counter is not zero
slt $t0, $s0, $s1
beq $t0, $0, else
li $v0, 4 
la $a0, sgt
syscall
j jump
else: 
li $v0, 4 
la $a0, fgt 
syscall 
jump:
li $v0, 10 #system call for exit
syscall

我也有相当多的麻烦得到"两个输入的数字等于工作。"我尝试使用三种情况，并有三个单独的标签:发送我的代码。但这并没有奏效。我不知道发生了什么。

Answer 1

这是个小错误。

查看循环前一行:

move $t2, $a0

您显然试图将总和移动到$t2，但$a0包含bin的地址。

将这行改为:

move $t2, $s2

一切正常