我正在尝试在文档中查找占位符文本(占位符如下所示:{{Placeholder}}
),然后获取它所在的节点,然后向节点添加一个属性。到目前为止,我能够找到占位符,但我不知道它是哪个元素分开的。当前的代码将我在这里写入控制台 3 次,因为它位于 3 个节点中:html
、body
和 h1
。它如何获取项目的实际父节点?
JavaScript:
function getPlaceholders(){
var elements = document.getElementsByTagName("*");
for(var e in elements){
var element = elements[e];
var html = element.innerHTML;
if(html && (matches = html.match(/{{(.+)}}/g))){
console.log("I am here");
}
}
}
.HTML:
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
</head>
<body>
<h1>Hello {{name}}!</h1>
</body>
</html>
这有效:(代码来自这里)
function getPlaceholders(){
var elements = document.getElementsByTagName("*");
for(var e in elements){
var element = elements[e];
child = element.firstChild,
texts = [];
while (child) {
if (child.nodeType == 3) {
texts.push(child.data);
}
child = child.nextSibling;
}
var html = texts.join("");
if(html && (matches = html.match(/{{(.+)}}/g))){
console.log(html);
}
}
}
http://jsfiddle.net/wumm/2VjVa/(忽略第一个日志,这只是jsfiddle的构建方式)
我相信
这只能通过递归来实现
function getPlaceholders(elem) {
// we search for the {{...}} pattern ONLY for this element
var html = elem.firstChild.data;
if(html && (matches = html.match(/{{(.+)}}/g))){
console.log(elem, "I am here");
}
// if there are any descendants of this elem, we also call the getPlaceholders function for them
var elements = elem.children;
if (elements.length) {
for(var i = 0; i < elements.length; i++) {
getPlaceholders(elements[i]);
}
}
}
//starting at the body
getPlaceholders(document.body);
下面是一个示例:http://jsfiddle.net/Ng7j8/