如何将 bash 脚本的一行制作成多行

Question

我绑在一起，让我的一些bash脚本在眼睛上更容易一些。假设我有这个脚本并且它工作正常。

if [ "$PASSWDCHECK" = "<title>401 Authorization Required</title>" ]
then echo "The Subsubscription password is wrong" ; exit
else mkdir /home/"$USERNAME"/src && mkdir /opt/logstash && mkdir /etc/snort && mkdir /etc/snort/rules/
fi

我想让它更像这样，但它无法执行。我错过了什么？

if [ "$PASSWDCHECK" = "<title>401 Authorization Required</title>" ]
then echo "The Subsubscription password is wrong" ; exit
else mkdir /home/"$USERNAME"/src  &&
    mkdir /opt/logstash  &&
    mkdir /etc/snort  &&
    mkdir /etc/snort/rules/  &&
fi

Answer 1

您需要

将放在每行的末尾，而不是放在&&之前。确保后没有空格。

Answer 2

只要&&是该行的最后一个非空格标记，该命令将自动继续到下一行。

if [ "$PASSWDCHECK" = "<title>401 Authorization Required</title>" ]
then echo "The Subsubscription password is wrong" ; exit
else mkdir /home/"$USERNAME"/src &&
     mkdir /opt/logstash &&
     mkdir /etc/snort &&
     mkdir /etc/snort/rules/
fi

&&列表联接两个命令，因此解析器知道应丢弃第二个命令之前的换行符。

Answer 3

if [ "$PASSWDCHECK" = "<title>401 Authorization Required</title>" ]
then echo "The Subsubscription password is wrong" ; exit
else 
  mkdir /home/"$USERNAME"/src && 
  mkdir /opt/logstash && 
  mkdir /etc/snort && 
  mkdir /etc/snort/rules/
fi