XSLT 1.0中的序列编号

Question

嗨，需要一些帮助，以 XSLT 格式化为 element tag 创建一个序列编号。大多数是元素标签错过了一些数字，我需要以顺序格式获得输出，如下所示，通过将丢失的数字添加到 element tag 中，以座位标签。

在此方面的任何帮助都非常感谢。

。

输入

<book>
<Seat>
    <seatNumber>12A</seatNumber>
    <Element>1</Element>
    <Number>1</Number>
</Seat>
<Seat>
    <seatNumber>12B</seatNumber>
    <Element>3</Element>
    <Number>1</Number>
</Seat>
<Seat>
    <seatNumber>12C</seatNumber>
    <Element>4</Element>
    <Number>1</Number>
</Seat>
<Seat>
    <seatNumber>12D</seatNumber>
    <Element>5</Element>
    <Number>1</Number>
</Seat>
<Seat>
    <seatNumber>12E</seatNumber>
    <Element>7</Element>
    <Number>1</Number>
</Seat>
</book>

输出

<book>
<Seat>
    <seatNumber>12A</seatNumber>
    <Element>1</Element>
    <Number>1</Number>
</Seat>
<Seat>
    <seatNumber>12B</seatNumber>
    <Element>2</Element>
    <Number>1</Number>
</Seat>
<Seat>
    <seatNumber>12C</seatNumber>
    <Element>3</Element>
    <Number>1</Number>
</Seat>
<Seat>
    <seatNumber>12D</seatNumber>
    <Element>4</Element>
    <Number>1</Number>
</Seat>
<Seat>
    <seatNumber>12E</seatNumber>
    <Element>5</Element>
    <Number>1</Number>
</Seat>
</book>

Answer 1

以这种方式尝试：

XSLT 1.0

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<!-- identity transform -->
<xsl:template match="@*|node()">
    <xsl:copy>
        <xsl:apply-templates select="@*|node()"/>
    </xsl:copy>
</xsl:template>
<xsl:template match="Element">
    <xsl:copy>
        <xsl:number count="Seat"/>
    </xsl:copy>
</xsl:template>
</xsl:stylesheet>