我的问题是python上此查询的scala(java)变体。
特别是我有一个字符串val myStr = "Shall we meet at, let's say, 8:45 AM?"
。我想将其引入和保留分界符(除了whitespace之外)。如果我的定界符只是字符,例如.
,:
,?
等,我可以做:
val strArr = myStr.split("((\s+)|(?=[,.;:?])|(?<=\b[,.;:?]))")
产生
[Shall, we, meet, at, ,, let's, say, ,, 8, :, 45, AM, ?]
但是,我希望使时间签名\d+:\d+
成为定界符,并且仍然希望保留它。所以,我想要的是
[Shall, we, meet, at, ,, let's, say, ,, 8:45, AM, ?]
注意:
- 在拆分语句的表达式中添加分离的
(?=(\d+:\d+))
没有帮助 - 在时间签名之外,
:
本身就是一个定界线
我怎么能实现这一目标?
我建议我匹配所有令牌,而不是分开字符串,因为这样您可以以更好的方式控制自己获得的东西:
bd{1,2}:d{2}b|[,.;:?]+|(?:(?!bd{1,2}:d{2}b)[^s,.;:?])+
请参阅正则演示。
我们开始匹配最特定的模式,最后一个是最通用的模式。
详细信息
-
bd{1,2}:d{2}b
-1至2位数字,:
,2个用字边界包含的数字 -
|
-或 -
[,.;:?]+
-1或更多,
,.
,;
,:
,?
chars -
|
-或 -
(?:(?!bd{1,2}:d{2}b)[^s,.;:?])+
-匹配任何不是我们的定界线char或whitespace([^s,.;:?]
)的字符,而不是时间字符串的起点。
考虑此片段:
val str = "Shall we meet at, let's say, 8:45 AM?"
var rx = """bd{1,2}:d{2}b|[,.;:?]+|(?:(?!bd{1,2}:d{2}b)[^s,.;:?])+""".r
rx findAllIn str foreach println
输出:
Shall
we
meet
at
,
let's
say
,
8:45
AM
?
/**
* StringPatternTokenizer is simlular to java.util.StringTokenizer
* But it uses regex string as the tokenizer separator.
* See inside method #testCase for detail usage.
*/
public class StringPatternTokenizer {
Pattern pattern;
public StringPatternTokenizer(String regex) {
this.pattern = Pattern.compile(regex);
}
public void getTokens(String str, NextToken nextToken) {
Matcher matcher = pattern.matcher(str);
int index = 0;
Result result = null;
while (matcher.find()) {
if (matcher.start() > index) {
result = nextToken.visit(null, str.substring(index, matcher.start()));
}
if (result != Result.STOP) {
index = matcher.end();
result = nextToken.visit(matcher, null);
}
if (result == Result.STOP) {
return;
}
}
if (index < str.length()) {
nextToken.visit(null, str.substring(index));
}
}
enum Result {
CONTINUE,
STOP,
}
public interface NextToken {
Result visit(Matcher matcher, String str);
}
/***********************************/
/***** test cases FOR IT ***********/
/***********************************/
public void testCase() {
// as a test, it tries access tokenizer result for each part,
// then replace variable parts by given values.
// And finally, we collect the result target string as output.
String strSource = "My name is {{NAME}}, nice to meet you.";
String strTarget = "My name is TokenTst, nice to meet you.";
// separator pattern for: variable names in two curly brackets
String variableRegex = "\{\{([A-Za-z]+)\}\}";
// variable values
org.json.JSONObject data = new org.json.JSONObject(
java.util.Collections.singletonMap("NAME", "TokenTst")
);
StringBuilder sb = new StringBuilder();
new StringPatternTokenizer(variableRegex)
.getTokens(strSource, (matcher, str) -> {
sb.append(matcher == null ? str
: data.optString(matcher.group(1), ""));
return StringPatternTokenizer.Result.CONTINUE;
});
// check the result as expected
org.junit.Assert.assertEquals(strTarget, sb.toString());
}
}