如何返回一些内容的.net流，但一路上压缩它

Question

我有一个很大的XDocument。我正试着把这个输出到某个地方:

public StreamResponse(Func<System.IO.Stream> source)

要做到这一点，我做了:

Stream stream = new MemoryStream();  // Create a stream
xmlDocument.Save(stream);      // Save XDocument into the stream
stream.Position = 0;
return new StreamResponse(() => stream);

，这很好。

现在，是否有可能改变这一点，以便我输出内存流的ZIP。

like this => XDocument => MemoryStream => ZIP Stream => stream-end-point

Answer 1

Stream stream = new MemoryStream();  // Create a stream
Stream compressed = new System.IO.Compression.GZipStream(stream, System.IO.Compression.CompressionLevel.Optimal);
xmlDocument.Save(compressed);      // Save XDocument into the stream
compressed.Position = 0;
return new StreamResponse(() => stream);

文档:GZipStream

Answer 2

是的，使用DotNetZip将内存流传递给save方法。像这样:

     using (ZipFile zip = new ZipFile())
     {
         // add this map file into the "images" directory in the zip archive
         zip.AddFile("c:\images\personal\7440-N49th.png", "images");
         // add the report into a different directory in the archive
         zip.AddFile("c:\Reports\2008-Regional-Sales-Report.pdf", "files");
         zip.AddFile("ReadMe.txt");
         zip.Save(myStream);
     }

Answer 3

GZipStream在这里拯救你!

从MSDN:

GZipStream类

提供用于压缩和解压缩流的方法和属性。

https://msdn.microsoft.com/en-us/library/system.io.compression.gzipstream%28v=vs.110%29.aspx