Hangman:如果正确的按钮点击应用程序挂起

Question

在我的hangman应用程序中，我为用户创建了一组按钮，然后从文件中随机选择在hangman应用中猜测的单词。。。这个单词是用JLabel打印的。。。但是，只要点击一个按钮，应用程序就会冻结。有人能告诉我这件事发生了吗。。。

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我是如何创建按钮的

for(char i = 'A'; i <= 'Z'; i++){
    String buttonText = new Character(i).toString();
    JButton button = getButton(buttonText);
    panel1.add(button);
}

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按钮ActionListener

public JButton getButton(final String text){
    final JButton button = new JButton(text);
    button.addActionListener(new ActionListener(){
        public void actionPerformed(ActionEvent e){
            if(original.toUpperCase().indexOf(button.getText())!=-1){
                guessString = text;
                guessLetter = guessString.charAt(0);
                StringBuilder builder = new StringBuilder(secret);
                while(error < 6){
                }
                for (int i = 0; i < original.length(); i++){
                    if (original.charAt(i) == guessLetter){
                        builder.setCharAt(i, guessLetter);
                    }
                }
                secret = builder.toString();
            }
            else{
                JOptionPane.showMessageDialog(null, "There is no " + text );
                error++;
                if(error >= 0) imageName = "hangman1.jpg";
                if(error >= 1) imageName = "hangman2.jpg";
                if(error >= 2) imageName = "hangman3.jpg";
                if(error >= 3) imageName = "hangman4.jpg";
                if(error >= 4) imageName = "hangman5.jpg";
                if(error >= 5) imageName = "hangman6.jpg";
                if(error >= 7) imageName = "hangman7.jpg"; 
            }
        }
    });
    return button;
}

Answer 1

如果error小于6，则在actionPerformed中有一个无限循环。

while(error < 6) {
}