更快地使用Java身份验证Congnito JWT令牌的方法

Question

我正在做以下

String region = "us-east-1";
String poolID = "us-east-1_whatever";
public Boolean valid() {
    try {
        String cognitoUrl = String.format("https://cognito-idp.%s.amazonaws.com/%s/.well-known/jwks.json", region, poolID);
        JwkProvider provider = new UrlJwkProvider(new URL(cognitoUrl));
        // got the value from the cognito url
        Jwk jwk = provider.get("value");
        RSAPublicKey publicKey = (RSAPublicKey) jwk.getPublicKey();
        Algorithm algorithm = Algorithm.RSA256(publicKey, null);
        String iss = String.format("https://cognito-idp.%s.amazonaws.com/%s", region, poolID);
        JWTVerifier verifier = JWT.require(algorithm).withIssuer(iss).build();
        verifier.verify(token);
    } catch (Exception err) {
        return false;
    }
    return true;
}

，但看起来很懒惰。如何更快地验证令牌？我正在使用

compile group: 'com.auth0', name: 'jwks-rsa', version: '0.3.0'
compile 'com.auth0:java-jwt:3.8.1'

Answer 1

亚马逊建议每次使用众所周知的JWK URL，如其支持存储库中所述。

缓存不是建议的做法，因为该值会发生变化。因此，我建议继续您当前的方法以确保具有最佳安全性的相同功能。