ListView in React Native and Firebase

Question

我已经能够使用firebase Authentication服务登录/登录使用React Anditial App中在Firebase数据库中添加/删除项目。但问题是我只需要显示项目在一个已经登录的一个用户中，并非数据库中的所有可用数据。我还设法使会话中的用户ID已连接。这是我的代码：...我想我需要在列表视图中使用过滤器，但我不确定

constructor(props) {
        super(props);
        this.tasksRef = this.props.firebaseApp.database().ref("/item");
        const dataSource = new ListView.DataSource({
            rowHasChanged: (row1, row2) => row1 !== row2,
        });
        this.state = {
            uid: " ",
            user:null,
            loading: true,
            dataSource: dataSource,
            newTask: 
        };
    }  
    componentDidMount() {
        this.listenForTasks(this.tasksRef);  
    }
    listenForTasks(tasksRef) {
        tasksRef.on('value', (dataSnapshot) => {
            var tasks = [];
            dataSnapshot.forEach((child) => {
                tasks.push({
                    name: child.val().name,
                    type: child.val().type,
                    id: child.val().id,
                    _key: child.key
                });
            });
                this.setState({
                dataSource: this.state.dataSource.cloneWithRows(tasks)
            });
        });
    }
    componentWillMount() {
        const userData = this.props.firebaseApp.auth().currentUser;
          this.setState({
            user: userData,
            uid: userData.uid,
            loading: false
        });
    }
    _addTask() {
        if (this.state.newTask === "") {
            return;
        }
        if (this.state.newTask && this.state.uid) {
            this.tasksRef.push({
                name: this.state.newTask,
                type: this.state.newType,
                id: this.state.uid,
            });
        }
        this.setState({newTask: ""});
        this.setState({newType: ""});
        this.setState({uid: ""});
        alert("Task added successfully");
    }
    _renderItem(task) {
        const onTaskCompletion = () => {
            this.tasksRef.child(task._key).remove()
        };
        return (
            <ListItem task={task} onTaskCompletion={onTaskCompletion} />
        );
    }
    render() {
        return (
            <View style={styles.container}>
                <StatusBar title="to do List"/>                    
                <View style={accountStyles.email_container}>
                    <Text style={accountStyles.email_text}>{this.state.user.email}</Text>
                    <TouchableHighlight onPress={this.logout.bind(this)} style={styles.primaryButton}>
                        <Text style={styles.primaryButtonText}>Logout</Text>
                    </TouchableHighlight>
                </View>
                <ListView
                    dataSource={this.state.dataSource}
                    enableEmptySections={true}
                    renderRow={this._renderItem.bind(this)}
                    style={styles.listView}/>
                <TextInput
                    value={this.state.newTask}
                    style={styles.textEdit}
                    onChangeText={(text) => this.setState({newTask: text})}
                    placeholder="New Task"
                />
                <TextInput
                    value={this.state.newType}
                    style={styles.textEdit}
                    onChangeText={(text1) => this.setState({newType: text1})}
                    placeholder="New Type"
                />
                <FloatingActionButton
                    hideShadow={true}
                    buttonColor="rgba(231,76,60,1)"
                    onPress={this._addTask.bind(this)}/>
            </View>
        );
    }
    logout() {
        this.props.firebaseApp.auth().signOut().then(() => {
            this.props.navigator.push({
                component: Login
            });
        });
    }
}

Answer 1

https://www.firebase.com/docs/security/guide/guide/index.html您需要在firebase中设置特定于用户的规则。这将使您的查询只为特定用户发送相关信息。

当我有同样的问题时，我做了这个人在第一个响应firebase中所说的话 - 如何列出用户特定数据？

"我按组ID或用户ID存储记录："

@user3521011我的代码示例：

    static setUserName(userId, userName) {
    let userNamePath = "/user/" + userId + "/details";
    return firebase.database().ref(userNamePath).update({
        userName: userName
    })
}