如何使用项目/构建.Scala生成Java游戏项目

Question

我使用playframework2.2:尝试构建一个游戏支持项目。

在我的构建。scala中，我想添加play.Project.playJavaSetting:

val main = play.Project(appName, appVersion, appDependencies)
.settings(play.Project.playJavaSettings)   //error here
.settings(
    resolvers += "webjars" at "http://webjars.github.com/m2",
    resolvers += "typesafe" at "http://repo.typesafe.com/typesafe/release" 
)

错误是:

[error] F:gitplay-example-formprojectBuild.scala:19: overloaded method value
settings with alternatives:
[error]   (ss: sbt.Def.Setting[_]*)sbt.Project <and>
[error]   => Seq[sbt.Def.Setting[_]]
[error]  cannot be applied to (Seq[sbt.Setting[_]])
[error]         .settings(play.Project.playJavaSettings)
[error]          ^

如果我不添加playJavaSetting，它会给我错误的收集应用，我的意思是:

    val main = play.Project(appName, appVersion, appDependencies)
//.settings(play.Project.playJavaSettings)   

，错误是:

[error]   required: play.api.data.Form<StudentFormData>,scala.collection.immutab
le.Map<String,Object>,scala.collection.immutable.List<String>,scala.collection.i
mmutable.Map<String,Object>,scala.collection.immutable.Map<String,Object>
[error]   found: play.data.Form<StudentFormData>,java.util.Map<String,Boolean>,j
ava.util.List<String>,java.util.Map<String,Boolean>,java.util.Map<String,Boolean

你可以看到框架应用了scale .collection.immutable. list而不是play.util。列表，如果我真的想应用java集合如何在构建中设置环境设置。scala文件?

Answer 1

你应该改变

.settings (play.Project.playJavaSettings)

.settings (play.Project。playJavaSettings: _ *)

将settings方法声明为def settings(ss: Setting[_]*)，这意味着它接受Setting[_]类型的重复参数。play.Project.playJavaSettings类型为Seq[Setting[_]]。要将一种类型转换为另一种类型，Scala有一个特殊的类型注释。

如果您对细节感兴趣，请查看4.6.2 Scala语言规范中的重复参数