在下面的场景中,我无法找出一种方法来将属性节点附加到输出节点。
输入xml:<record>
<user>
<field name="LastName">user33</field>
<field name="FirstName">user33</field>
<field name="Title"/>
<field name="Email">user33@gmail.com</field>
<field name="WorkPhone"/>
<field name="Fax"/>
<field name="Description">new user</field>
<field name="Group Member"> group1</field>
</user>
</record>
预期输出:<add class="user" id-val="user33 user33" >
<add-value attr="LastName">
<value type="string">user33</value>
</add-attr>
<add-value attr="FirstName">
<value type="string">user33</value>
</add-value>
<add-value attr="Email">
<value type="string">user33@gamil.com</value>
</add-value>
<add-value attr="Description">
<value type="string">new user</value>
</add-value>
</add>
这是到目前为止我看到的XSLT代码片段。
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:variable name="lessThan" select="'<'"/>
<xsl:variable name="GreaterThan" select="'>'"/>
<xsl:template match="user">
<xsl:variable name="temp1" select="concat(field[@name=$srcdn-field-name1],' ')"/>
<xsl:variable name="temp2" select="concat($temp1,field[@name=$srcdn-field-name2])"/>
<xsl:variable name="src" select="translate($temp2,'+=,.','-----')"/>
<xsl:value-of disable-output-escaping="yes" select="$lessThan"/>
<xsl:text>add</xsl:text>
<xsl:value-of disable-output-escaping="yes" select="$GreaterThan"/>
<!-- it is required to add attribute id-val to element <add> with value of $src-->
<xsl:for-each select="field[string()]">
<xsl:variable name="fieldValue" select="normalize-space(.)"/>
<xsl:choose>
<xsl:when test="@name !='Group Member'">
<add-value attr="{@name}">
<value type="string">
<xsl:value-of select="$fieldValue"/>
</value>
</add-value>
</xsl:when>
<xsl:otherwise>
<xsl:value-of disable-output-escaping="yes" select="$lessThan"/>
<xsl:text>/add</xsl:text>
<xsl:value-of disable-output-escaping="yes" select="$GreaterThan"/>
<!--perform some other operations-->
</xsl:otherwise>
</xsl:choose>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
现在我的要求是将id-val和class作为<add>
的属性。在这种情况下,<xsl:attribute>
不起作用。我需要对xslt进行哪些更改?
你不能给元素以外的东西添加属性。这是不尝试手动构造开始和结束标记的众多原因之一。试试这个:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:template match="user">
<xsl:variable name="temp1" select="concat(field[@name=$srcdn-field-name1],' ')"/>
<xsl:variable name="temp2" select="concat($temp1,field[@name=$srcdn-field-name2])"/>
<xsl:variable name="src" select="translate($temp2,'+=,.','-----')"/>
<add class="user" id-val="{$src}">
<!-- it is required to add attribute id-val to element <add> with value of $src-->
<xsl:for-each select="field[string()]
[not((. | preceding-sibling::field)
[@name = 'Group Member'])]">
<add-value attr="{@name}">
<value type="string">
<xsl:value-of select="normalize-space()"/>
</value>
</add-value>
</xsl:for-each>
</add>
</xsl:template>
</xsl:stylesheet>