没有调用XMPPFramework发送元素方法

Question

你好，我正在制作一个使用XMPPFramework的聊天应用程序。

我已经在我的项目中设置了XMPPFramework参考这个链接:-http://code.tutsplus.com/tutorials/building - - jabber客户机- ios xmpp -设置-手机- 7190

发送消息的代码:-

    NSXMLElement *body = [NSXMLElement elementWithName:@"body"];
    [body setStringValue:messageStr];
    NSXMLElement *message = [NSXMLElement elementWithName:@"message"];
    [message addAttributeWithName:@"type" stringValue:@"chat"];
    [message addAttributeWithName:@"to" stringValue:fnjid];
    [message addChild:body];
    [self.xmppStream sendElement:message];

这段代码工作得很好，但现在这是不工作…方法"发送元素"没有调用，它在xmppstream类中。

- (void)sendElement:(NSXMLElement *)element

此方法在连接到服务器时调用，但仅在发送消息时不起作用

Answer 1

可能您的复方和授权有问题?

- (void)xmppStreamDidConnect:(XMPPStream *)sender
{
    isXmppConnected = YES;
    NSError *error = nil;
    if (![[self xmppStream] authenticateWithPassword:password error:&error])
    {
    }
}
And
- (void)xmppStreamDidAuthenticate:(XMPPStream *)sender
{
    XMPPPresence *presence = [XMPPPresence presenceWithType:@"available"];
    [[self xmppStream] sendElement:presence];
}

In this case, the method does not work correctly , because state != STATE_XMPP_CONNECTED
- (void)sendElement:(NSXMLElement *)element
{
 if (element == nil) return;
 dispatch_block_t block = ^{ @autoreleasepool {
  if (state == STATE_XMPP_CONNECTED)
  {
   [self sendElement:element withTag:TAG_XMPP_WRITE_STREAM];
  }
  else
  {
   [self failToSendElement:element];
  }
 }};
 if (dispatch_get_specific(xmppQueueTag))
  block();
 else
  dispatch_async(xmppQueue, block);
}