我正在尝试按键搜索YouTube视频,就像在golang示例中一样。我稍微修改了该代码,使其多次按不同的键进行搜索。
当我搜索一次就可以了。
func main() {
result1, err1 := SearchYoutubeByKey("hello")
if err1 != nil {
panic(err1)
}
fmt.Println(result1)
// result2, err2 := SearchYoutubeByKey("world")
// if err2 != nil {
// panic(err2)
// }
// fmt.Println(result2)
}
但是如果我搜索两次...
func main() {
result1, err1 := SearchYoutubeByKey("hello")
if err1 != nil {
panic(err1)
}
fmt.Println(result1)
result2, err2 := SearchYoutubeByKey("world")
if err2 != nil {
panic(err2)
}
fmt.Println(result2)
}
。然后它惊慌失措并显示错误消息...
flag redefined: query
。在线。。。
query := flag.String("query", str, "Search term")
完整代码:
package main
import (
"code.google.com/p/google-api-go-client/googleapi/transport"
"code.google.com/p/google-api-go-client/youtube/v3"
"flag"
"fmt"
"net/http"
)
var (
maxResults = flag.Int64("max-results", 25, "Max YouTube results")
service *youtube.Service
response *youtube.SearchListResponse
)
const developerKey = "youtube developer key"
type YoutubeSearchResult struct {
Title, YoutubeId string
}
func SearchYoutubeByKey(str string) (result []*YoutubeSearchResult, err error) {
query := flag.String("query", str, "Search term")
flag.Parse()
client := &http.Client{
Transport: &transport.APIKey{Key: developerKey},
}
service, err = youtube.New(client)
if err != nil {
return
}
// Make the API call to YouTube.
call := service.Search.List("id,snippet").
Q(*query).
MaxResults(*maxResults)
response, err = call.Do()
if err != nil {
return
}
// Iterate through each item and add it to the correct list.
for _, item := range response.Items {
switch item.Id.Kind {
case "youtube#video":
result = append(result, &YoutubeSearchResult{Title: item.Snippet.Title, YoutubeId: item.Id.VideoId})
}
}
return
}
func main() {
result1, err1 := SearchYoutubeByKey("hello")
if err1 != nil {
panic(err1)
}
fmt.Println(result1)
result2, err2 := SearchYoutubeByKey("world")
if err2 != nil {
panic(err2)
}
fmt.Println(result2)
}
因此,不可能在网站上使用此代码。只有第一个用户才能第一次搜索,其他用户将失败。
我无法在运行时更改标志,但是如何在一个程序中按 2 个不同的键进行搜索?
更新
工作解决方案:
package main
import (
"code.google.com/p/google-api-go-client/googleapi/transport"
"code.google.com/p/google-api-go-client/youtube/v3"
"flag"
"fmt"
"net/http"
)
var (
maxResults = flag.Int64("max-results", 25, "Max YouTube results")
service *youtube.Service
response *youtube.SearchListResponse
query = flag.String("query", "str", "Search term")
)
const developerKey = "youtube api key"
type YoutubeSearchResult struct {
Title, YoutubeId string
}
func SearchYoutubeByKey(str string) (result []*YoutubeSearchResult, err error) {
flag.Parse()
client := &http.Client{
Transport: &transport.APIKey{Key: developerKey},
}
service, err = youtube.New(client)
if err != nil {
return
}
// Make the API call to YouTube.
call := service.Search.List("id,snippet").
Q(str).
MaxResults(*maxResults)
response, err = call.Do()
if err != nil {
return
}
// Iterate through each item and add it to the correct list.
for _, item := range response.Items {
switch item.Id.Kind {
case "youtube#video":
result = append(result, &YoutubeSearchResult{Title: item.Snippet.Title, YoutubeId: item.Id.VideoId})
}
}
return
}
func main() {
result1, err1 := SearchYoutubeByKey("hello")
if err1 != nil {
panic(err1)
}
fmt.Println(result1)
result2, err2 := SearchYoutubeByKey("world")
if err2 != nil {
panic(err2)
}
fmt.Println(result2)
}
紧急消息会告诉您到底出了什么问题。命令行标志应仅定义一次。如果您尝试在运行时重新定义它们,它会崩溃。