使用比较器对字符串列表进行排序

Question

我有字符串。BOMResult：

1|00022954|41.418 2|00022951|1.0 3|00022945|41.575 3|00022944|41.684 3|00022944|41.778 3|00022944|41.871 3|00022946|42.918 3|00022944|41.918 3|00022944|41.825 3|00022944|41.731 3|00022945|41.621 3|00022953|41.512 4|00022957|0.0 5|00022947|42.809 5|00022942|42.918 5|00022948|43.918 5|00022947|42.871 5|00022950|42.746 4|00022952|1.0 5|00022941|41.246 5|00020472|41.184 2|00022958|0.0 3|00022945|39.621 3|00022944|39.731 3|00022944|39.84 3|00022944|39.949 3|00022944|39.887 3|00022944|39.793 3|00022945|39.684 3|00022956|39.512 4|00022959|1.0 5|00022941|40.762 5|00022943|40.699 4|00022957|0.0 5|00022947|42.809 5|00022942|42.918 5|00022948|43.918 5|00022947|42.871 5|00022950|42.746 3|00022949|40.996 3|00022944|39.996

在此处输入图像描述

当竖线 (|( 被分隔时，

第一个字符串是级别。

最后一个字符串是要排序的基础。

如果级别相等，则对字符串进行排序。

List<String> rowList = Arrays.asList(BOMResult.split("n"));
Collections.sort(rowList, new Comparator<String>() {
@Override
public int compare(String s1, String s2) {
String array1[] = s1.split("\|");
String array2[] = s2.split("\|");
int i1 = Integer.parseInt(array1[0]);
int i2 = Integer.parseInt(array2[0]);
if (i1 == i2) {
return Double.valueOf(array1[array1.length-1]).compareTo(Double.valueOf(array2[array2.length-1]));
} else {
return 0;
}
}
});
BOMResult = String.join("n", rowList);

当前结果：

1|00022954|41.418
2|00022951|1.0
3|00022953|41.512
3|00022945|41.575
3|00022945|41.621
3|00022944|41.684
3|00022944|41.731
3|00022944|41.778
3|00022944|41.825
3|00022944|41.871
3|00022944|41.918
3|00022946|42.918
4|00022957|0.0
5|00020472|41.184
5|00022941|41.246
5|00022950|42.746
5|00022947|42.809
5|00022947|42.871
5|00022942|42.918
5|00022948|43.918
4|00022952|1.0
2|00022958|0.0
3|00022956|39.512
3|00022945|39.621
3|00022945|39.684
3|00022944|39.731
3|00022944|39.793
3|00022944|39.84
3|00022944|39.887
3|00022944|39.949
4|00022957|0.0
4|00022959|1.0
5|00022943|40.699
5|00022941|40.762
5|00022950|42.746
5|00022947|42.809
5|00022947|42.871
5|00022942|42.918
5|00022948|43.918
3|00022944|39.996
3|00022949|40.996

我想在同一级别排序，即使行不同。

预期成果：

1|00022954|41.418
2|00022958|0.0
3|00022956|39.512
3|00022945|39.621
3|00022945|39.684
3|00022944|39.731
3|00022944|39.793
3|00022944|39.84
3|00022944|39.887
3|00022944|39.949
4|00022957|0.0
4|00022959|1.0
5|00022943|40.699
5|00022941|40.762
5|00022950|42.746
5|00022947|42.809
5|00022947|42.871
5|00022942|42.918
5|00022948|43.918
3|00022944|39.996
3|00022949|40.996
2|00022951|1.0
3|00022953|41.512
3|00022945|41.575
3|00022945|41.621
3|00022944|41.684
3|00022944|41.731
3|00022944|41.778
3|00022944|41.825
3|00022944|41.871
3|00022944|41.918
3|00022946|42.918
4|00022957|0.0
5|00020472|41.184
5|00022941|41.246
5|00022950|42.746
5|00022947|42.809
5|00022947|42.871
5|00022942|42.918
5|00022948|43.918
4|00022952|1.0

Answer 1

首先为记录创建一个数据对象
(将名称替换为实际属性，即first->level(：

public static class Data {
private final int first;
private final String second;
private final double third;
public Data(int first, String second, double third) {
this.first = first;
this.second = second;
this.third = third;
}
public int getFirst() {  return first; }
public String getSecond() { return second; }
public double getThird() {  return third; }
@Override
public String toString() {
return first + "|" + second + "|" + third;
}
}

之后，您可以通过链接比较器对此类记录的列表进行排序。 示例(按第一个、第二个、第三个排序(：

List<Data> list = new LinkedList<>();
list.add(new Data(1, "00022954", 41.418));
list.add(new Data(2, "00022951", 1.0));
list.add(new Data(3, "00022953", 41.512));
list.add(new Data(3, "00022945", 41.575));
list.add(new Data(3, "00022945", 41.621));
// shuffle to test sorting
Collections.shuffle(list);
// sort the data
Collections.sort(list, 
Comparator.comparing(Data::getFirst)
.thenComparing(Data::getSecond)
.thenComparing(Data::getThird));
// output the data
list.forEach(System.out::println);

Answer 2

您可以合并同一比较器中的第一列和最后一列，如下所示：

Collections.sort(rowList, new Comparator<String>() {
@Override
public int compare(String s1, String s2) {
String array1[] = s1.split("\|");
String array2[] = s2.split("\|");
Integer i1 = Integer.valueOf(array1[0].trim());
Integer i2 = Integer.valueOf(array2[0].trim());
return i1.compareTo(i2) + Double.valueOf(array1[array1.length-1]).compareTo(Double.valueOf(array2[array2.length-1]));
}
});

Answer 3

好的，试试这个：

Collections.sort(rowList, new Comparator<String>() {
@Override
public int compare(String s1, String s2) {
String array1[] = s1.split("\|");
String array2[] = s2.split("\|");
Integer i1 = Integer.valueOf(array1[0].trim());
Integer i2 = Integer.valueOf(array2[0].trim());
int res = i1.compareTo(i2);
if (res == 0) {
Double d1 = Double.valueOf(array1[array1.length - 1]);
Double d2 = Double.valueOf(array2[array2.length - 1]);
return d1.compareTo(d2);
}
return res;
}
});